The width is 2 and the length is 9 because 9 times 2 is 18 and 2 times 5 is 10. 10 minus 1 is 9 which then again 9 times 2 is 18 which is the area.
I believe 3-4 ships took part in the battle
(88sin20)(t - 16t²) = 0
(8(0.3090169944)(t - 16t²) = 0
(2.472135955)(t - 16t²) = 0
2.472135955t - 39.55417528t² = 0
Answer:
Answer has been attached above thanks