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4 years ago

Assume that there are 20 m&ms in a bowl (5 red, 11 yellow, 4 green).

Mathematics

1 answer:

Nina [5.8K]4 years ago

5 0

You're a bot. If you aren't I'm sorry but your name is like the exact same as a bunch of others

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What is 14=4xb+3 -------------------------------

Kipish [7]

Answer:

Step-by-step explanation:

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3 years ago

| <img src="https://tex.z-dn.net/?f=370%20%5Cdiv%20124780%20%5C%5C" id="TexFormula1" title="370 \div 124780 \\" alt="370 \div

Kay [80]

Answer:

Filipino ano sa palagay mo ang nadarama ng tiger sa oras na iyon answer

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3 years ago

Read 2 more answers

X2+4x+3 solve for x.

mario62 [17]

Answer:

(x+1)(x+3)

Step-by-step explanation:

Let's factor x^2+4x+3

x^2+4x+3

The middle number is 4 and the last number is 3.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get 4

Multiply together to get 3

Can you think of the two numbers?

Try 1 and 3:

1+3 = 4

1*3 = 3

Fill in the blanks in

(x+_)(x+_)

with 1 and 3 to get...

(x+1)(x+3)

4 0

3 years ago

What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

3 years ago

Use the image below, answer the following questions. Be sure to answer all 3 questions in order.

Nastasia [14]

Answer:

a. Yes

b. VT

c. Segment RQ

Step-by-step explanation:

a. Find the slope of RS and UV

Slope = rise/run

Slope of RS = rise/run = RQ/QS

Slope of RS = 6/6

Slope of RS = 1

Slope of UV = rise/run = UT/TV

Slope of UV = 3/3

Slope of UV = 1

Thus, TS and UV have equivalent slopes

b. Slope of VT:

VT is an horizontal line.

It has no rise. But only run.

Therefore, it's rise = 0, while run = VT = 3

Slope of VT = rise/run = 0/3

Slope of VT = 0

c. Vertical lines have undefined slope.

Segment RQ is vertical line and therefore has an undefined slope.

RQ has rise but no run.

Thus:

Rise = 6

Run = 0

Slope of Segment RQ = 6/0 (this can't divide)

Therefore, slope of Segment RQ is undefined.

3 0

3 years ago