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Tomtit [17]
3 years ago
12

In two or more complete sentences, give the solution and explain how you solved the system.

Mathematics
1 answer:
Triss [41]3 years ago
3 0
The system is:

i) y=-2x+3
ii) y=-2\cdot3^x.

Making y's equal, we have:

                      -2x+3=-2\cdot3^x.

Dividing all terms by -2, we have:

                      \displaystyle{ x- \frac{3}{2} =3^x.

Note that y=x- \frac{3}{2} is an increasing linear function. (Its graph is the same as y=x, only shifted 3/2 units down.)

The graph of this function is below the x-axis up to 3/2, where it cuts the x-axis, and then increases above the x-axis making an angle of 45° with the x-axis.

The graph of y=3^x is completely above the x-axis, and it rises much faster than the line. We could compare at 3/2, for example, where the linear function is 0. The exponential function takes the value 3^{\frac{3}{2}}\approx5.2 and is increasing very fast.


Thus, the graphs never meet, which means the system has no solution.


Answer: no solution.
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Tony is trying to find the solution of the system 2x - 4y +12 using elimination 3x + 4y = 48 He wrote these steps to solve the p
kobusy [5.1K]

Answer: Solution: (12, 3)

Step-by-step explanation:

2x - 4y = 12

3x + 4y = 48

Add both equations

5x = 60

Divide both sides by 5

x = 12

We can use the value of x to find y

3x + 4y = 48

3 (12) + 4y = 48

36 + 4y = 48

Subtract 36 from both sides

4y = 12

Divide both sides by 4

y = 3

Solution: (12, 3)

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3 years ago
A car passes a landmark traveling at a constant rate of 55 kilometers per hour. One hour later, a second car passes the same lan
yarga [219]
Recall your d = rt, distance = rate * time

one car is going at 55kph, at say hmmm "t" time
the second car zooms by at 75kph, an hour later, thus " t + 1 "

notice, overtaking the 1st car, simply means, the second car comes from behind approaches the first car from behind and "gets there", at that very second, both cars have travelled a distance, say "d"

if the first car travelled "d" kilometers
for the second car to "get there" has to had travelled "d" distance as well

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{first car}&d&55&t\\
\textit{second car}&d&75&t+1
\end{array}
\\\\\\
\begin{cases}
d=55t\\
d=75(t+1)\\
-------\\
55t=75(t+1)
\end{cases}

solve for "t"
7 0
3 years ago
Read 2 more answers
How do i find the roots of this equation: f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
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The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
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f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
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3 years ago
Select the two values of x that are roots of this equation.
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