Answer:
that answe is b
Step-by-step explanation:
b because i took this test
Answer:
6(y+1) Hope this helps!!
Step-by-step explanation:
52 is your answer
Hope this helps
He should use the Pythagorean Theorem to find the missing length.
Since KT is tangent to the circle and TL reaches the center of circle L, the measure of angle LTK is 90 degrees. This means that triangle LTK is a right triangle which means the Pythagorean Theorem can be used.
So,
TL²+(12)²=(13)²
=> TL²+144=169
=> TL²=25
=> TL = 5
Therefore, the radius of circle L is 5 feet.
Answer:
![Quarters = 41](https://tex.z-dn.net/?f=Quarters%20%3D%2041)
![Dimes = 18](https://tex.z-dn.net/?f=Dimes%20%3D%2018)
Step-by-step explanation:
Given
![Coins = 59](https://tex.z-dn.net/?f=Coins%20%3D%2059)
![Worth = \$12.05](https://tex.z-dn.net/?f=Worth%20%3D%20%5C%2412.05)
![d = dimes](https://tex.z-dn.net/?f=d%20%3D%20dimes)
![q = quarters](https://tex.z-dn.net/?f=q%20%3D%20quarters)
Required
The number of each coin
The total coins can be represented as:
![d + q = 59](https://tex.z-dn.net/?f=d%20%2B%20q%20%3D%2059)
![1\ quarter = \$0.25 \\ 1\ dime = \$0.10](https://tex.z-dn.net/?f=1%5C%20quarter%20%3D%20%5C%240.25%20%5C%5C%201%5C%20dime%20%3D%20%5C%240.10)
So, the worth of the coin is:
![0.25q + 0.10d = 12.05](https://tex.z-dn.net/?f=0.25q%20%2B%200.10d%20%3D%2012.05)
The equations to solve are:
![0.25q + 0.10d = 12.05](https://tex.z-dn.net/?f=0.25q%20%2B%200.10d%20%3D%2012.05)
![d + q = 59](https://tex.z-dn.net/?f=d%20%2B%20q%20%3D%2059)
Make d the subject in: ![d + q = 59](https://tex.z-dn.net/?f=d%20%2B%20q%20%3D%2059)
![d =59 - q](https://tex.z-dn.net/?f=d%20%3D59%20-%20q)
Substitute
in ![0.25q + 0.10d = 12.05](https://tex.z-dn.net/?f=0.25q%20%2B%200.10d%20%3D%2012.05)
![0.25q + 0.10(59 - q) = 12.05](https://tex.z-dn.net/?f=0.25q%20%2B%200.10%2859%20-%20q%29%20%3D%2012.05)
![0.25q + 5.9 - 0.10q = 12.05](https://tex.z-dn.net/?f=0.25q%20%2B%205.9%20-%200.10q%20%3D%2012.05)
Collect like terms
![0.25q - 0.10q = 12.05 - 5.9](https://tex.z-dn.net/?f=0.25q%20%20-%200.10q%20%3D%2012.05%20-%205.9)
![0.15q = 6.15](https://tex.z-dn.net/?f=0.15q%20%3D%206.15)
Solve for q
![q=\frac{6.15}{0.15}](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B6.15%7D%7B0.15%7D)
![q=41](https://tex.z-dn.net/?f=q%3D41)
Substitute
in ![d =59 - q](https://tex.z-dn.net/?f=d%20%3D59%20-%20q)
![d = 59 - 41](https://tex.z-dn.net/?f=d%20%3D%2059%20-%2041)
![d = 18](https://tex.z-dn.net/?f=d%20%3D%2018)
So:
![Quarters = 41](https://tex.z-dn.net/?f=Quarters%20%3D%2041)
![Dimes = 18](https://tex.z-dn.net/?f=Dimes%20%3D%2018)