Answer:
Dependent Value: Cost (C)
Independent Value: Bushels (B)
Step-by-step explanation:
You can make the letter D out of the side of the bar graph and the letter I on the bottom, this tells you the label on the side is the dependent and the label on the bottom is the independent. If you dont have a line graph then think about this sentence starter: ...... effects.......
Quote to make you happy:
Answer:
Given f(x) and g(x), please find (fog)(X) and (gof)(x) f(x) = 2x g(x) = x+3
Given f(x) and g(x), please find (fog)(X) and (gof)(x)
f(x) = 2x g(x) = x+3
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Quick Answer
(fog)(x) = 2x + 6
(gof)(x) = 2x + 3
Expert Answers
HALA718 eNotes educator| CERTIFIED EDUCATOR
f(x) = 2x
g(x) = x + 3
First let us find (fog)(x)
(fog)(x) = f(g(x)
= f(x+3)
= 2(x+3)
= 2x + 6
==> (fog)(x) = 2x + 6
Now let us find (gof)(x):
(gof)(x) = g(f(x)
= g(2x)
= 2x + 3
==> (gof)(x) = 2x + 3
Step-by-step explanation:
Answer:
12%
Step-by-step explanation:
1, a.) The two specific conjectures are in the first image.
1, b.) The two general conjectures are in the second image.
2, a.) Two specific conjectures for this pattern are:
- The common difference between two consecutive terms is 3.
- And the given difference is A.P.
2, b.) From our observation two general conjecture is that the given sequence is an arithmetic sequence and the common difference is 3.
For finding its nth term we can use the formula: a(n) = a + (n-1) x d.
2, c.) A formula for the given pattern is 5 + (n-1)3, where n is the number of the term.
Answer:
No, because as the x-values are increasing by a constant amount, the y-values are not being multiplied by a constant amount.
Step-by-step explanation:
We have a set of ordered pairs of the form (x, y)
If a function is exponential then the ratio between the consecutive values of y, is always equal to a constant.
This means that:
\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b
This is: y_2=by_1y2=by1
Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}
Observe that:
\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31
Then the values of y are not multiplied by a constant amount "b"
