In the number 668 the 6 in the hundreds place is _ the value of the 6 in the tens place
1 answer:
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Answer: 69,904
Explanation:
g(-16)= (-16)^4-(-16)^3+(-16)^2-(-16)
g(-16)= (65,536)-(-4,096)+(256)-(-16)
g(-16)= 65,536+4,096+256+16
g(-16)=69,904
Explanation:
g(-16)= (-16)^4-(-16)^3+(-16)^2-(-16)
g(-16)= (65,536)-(-4,096)+(256)-(-16)
g(-16)= 65,536+4,096+256+16
g(-16)=69,904