Answer:
2
Step-by-step explanation:
The range of class A is 5-0 = 5
The range of class B is 3-0 = 3
the difference between 3 and 5 is 2.
Answer:
option 4
Step-by-step explanation:
(f*g)(x) =(x² + x+ 1)*(x² - x -1)
= x²*(x² - x -1) + x(x² - x -1) + 1*( x² - x -1)
= x²*x² - x²*x -x²*1 + x*x² - x*x -x*1 + x² - x -1
= x⁴ - x³ - x² +x³ - x² - x + x² - x -1
= x⁴ - x³ + x³ - x² - x² + x² - x - x - 1
= x⁴ - x² - 2x - 1
A = 1/2 b h
5 = 1/2 (5) h
10 = 5h
h = 10/5
h = 2
answer
2
M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]
Answer:
25
Step-by-step explanation:
Given the function that represents the amount of mosquitoes as;
M(x) = -(x-5)² + 25
To get the maximum mosquitoes possible, we need to first find x;
At the maximum dM/dx = 0
dM//dx = -2(x-5)
0 = -2(x-5)
-2(x-5) = 0
-2x + 10 = 0
-2x = -10
x = 10/2
x = 5
Substitute x = 5 into the function;
M(5) = −(5−5)² +25
M(5) = 0+25
M(5) = 25
Hence the maximum number of mosquitoes is 25
