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2 years ago

14

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

1 answer:

cupoosta [38]2 years ago

5 0

Answer:

A. $G(x) = 7x^2$

D. No, because one x-value corresponds to two different y-values.

Step-by-step explanation:

If you were to vertically stretch the quadratic parent function, the correct answer would be "A," because you are stretching upwards, which in turn, also changes the y-values.

As you can see in the table, the x-value of 3 repeats, which cannot occur. Each input (x-value) can go to only one output (y-value). As a result, the table does not represent a function.

You might be interested in

Partial quotient for 654 divided by 3

Vladimir79 [104]

654 over 3 = divide the both 654 and 3 by 3.

It will give you 218 over 1.

So the answer is 218.

6 0

2 years ago

Rewrite using a fractional exponent<br><br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B7%5E2%7D" id="TexFormula1" title=

tangare [24]

Answer:

$7^{\frac{1}{3} }$

Step-by-step explanation:

Using the rule of exponents

$\sqrt[n]{a^{m} }$ ⇔ $a^{\frac{m}{n} }$ , then

$\sqrt[6]{7^{2} }$ = $7^{\frac{2}{6} }$ = $7^{\frac{1}{3} }$

8 0

2 years ago

Tan^2x+sec^2x=1 for all values of x. <br> true or false?

amid [387]

This is not true.

$\tan^2x+\sec^2x=\dfrac{\sin^2x}{\cos^2x}+\dfrac1{\cos^2x}=\dfrac{1-\cos^2x+1}{\cos^2x}=2\sec^2x-1$

$2\sec^2x-1=1\implies\sec^2x=1\implies\sec x=\pm1\implies x=n\pi$

where is $n$ is any integer. So suppose we pick some value of $x$ other than these, say $x=\dfrac\pi4$ . Then

$\tan^2\dfrac\pi4+\sec^2\dfrac\pi4=1+2=3\neq1$

5 0

2 years ago

Read 2 more answers

Y-5, y=2x^2-16x+29, use substitution to solve the system of equations

seraphim [82]

Answer:

2x^2-16x+34

Step-by-step explanation:

Since Y is equal to -5

And you substitute -5 in the equation.

You now have -5=2x^2-16x+29

Add 5 to both sides

5-5=2x^-16x+29+5

7 0

2 years ago

Sock hop (ExH). You have 10 pairs of socks, fi ve black and fi ve blue, but they are not paired up. Instead, they are all mixed

kvasek [131]

Answer:

Step-by-step explanation:

Total number of pairs of socks in a drawer = 10

Number of black pairs of socks = 5

Number of blue pairs of socks = 5

A. If you picked 2 socks [black] and [blue] 3rd pick guarantees you will have one pair of either blue or black

Number of socks you pull out to guarantee that you have a pair of one color = 3 socks

B. If you want to pick 2 good pairs and your 6 picks are worst case, so 7th pick of the socks will give you good pair of two colors.

Number of socks you pull out to have two good pairs = 7 socks

C. If you want to have a pair of black socks your worst case will be you pick all 10 blue socks so another 2 socks must be black.

Number of socks you pull out to have two black socks = 12 socks

4 0

3 years ago