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AveGali [126]
3 years ago
14

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

A. G(x) = 7x^2

D. No, because one x-value corresponds to two different y-values.

Step-by-step explanation:

If you were to vertically stretch the quadratic parent function, the correct answer would be "A," because you are stretching upwards, which in turn, also changes the y-values.

As you can see in the table, the x-value of 3 repeats, which cannot occur. Each input (x-value) can go to only one output (y-value). As a result, the table does not represent a function.

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You are designing a container in the shape of a cylinder. the the radius is six inches. you want the container to hold at least
scoray [572]

We have radius r= 6 inches and volume V≥ 324 pi inches∧3 we need H=?

We will use next formula to calculate height.

V= B * H = r∧2 pi * H

r∧2 pi * H ≥ 324 pi => 6∧2 pi * H ≥ 324 pi => 36 pi * H ≥ 324 pi

We will divide the both sides of the inequality with pi and get

36 * H ≥ 324 => H ≥ 324/36 => H ≥ 9 inches

Good luck!!!

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3 years ago
Who gets more chips: 5 people sharing 3 bags of chips or 7 people sharing 2 bags?
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6 0
3 years ago
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Write an equation of cosine function with amplitude 2 and a period 4pi
Arisa [49]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

now.. hmmm let's see, keeping in mind the template above

so, amplitude of 2, A=2, thus |A| = ±2, so, you can use either

and period of 4π, well, that simply means that 

\bf \cfrac{2\pi }{B}=4\pi \implies \cfrac{2\pi }{4\pi }=B\implies \cfrac{1}{2}=B\\\\
-----------------------------\\\\

\begin{array}{llll}
f(\theta)=&\pm 2cos&\left(\frac{1}{2}\theta  \right)\\
&\ \uparrow &\ \uparrow \\
&A&B
\end{array}
8 0
4 years ago
A model train has a scale of 1 in : 2 ft. If the model train is 9 in tall, then how tall is the real train?
mart [117]
A.) five feet tall

hope this helps!
5 0
4 years ago
The angles below are supplementary. What is the value of x? (5 points)
Mademuasel [1]

Answer:

Step-by-step explanation:

As the angles are supplementary, they sum up to 180

Hence, 3x+40+80=180

3x+120=180

3x=60

x=20

6 0
4 years ago
Read 2 more answers
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