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Mumz [18]
3 years ago
7

Caitlin wants to read for 90 minutes so far she has read 30% of her how much more longer does she need to read

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0
She read 27 minutes already (90 x .30) and has 63 minutes 1 hour and 3 minutes left (90-27).
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I need to know how to make it in its simplest form
Mrrafil [7]
Multiply denominator by whole number then add that number to the nominator. Which would be 5 times 1 plus 3. SO 5+3 IS 8 and you keep the denominator so the first one is 8/5
6 0
3 years ago
Which are the two number that multiply is 300 and subtraction is 35​
alukav5142 [94]

Answer:

15 and 20

Step-by-step explanation:

4 0
3 years ago
Picture shows the question. Please help!
zhenek [66]
Using the picture, we know (2x+6)+(5x-3)=24. Simplify to find x.

7x+3=24
7x=21
x=3

We know AB=2x+6, and x=3. Plug 3 in for x.
AB=2(3)+6.
AB=6+6
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6 0
3 years ago
An antique wooden chest has the shape of a rectangular prism. It has a width of 16 inches. Its length is 4 times its height. The
baherus [9]
The height is 4. (And the length is 64)
7 0
3 years ago
Read 2 more answers
A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points ex
Serga [27]
<h3>Answer:  127</h3>

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

  • first exam = 70
  • second exam = 80
  • third exam = 43
  • fourth exam = x+5

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

7 0
3 years ago
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