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11111nata11111 [884]
3 years ago
7

laura bought a square canvas to paint a picture of her cat. one side measures 22 centimeters. what is the area of canvas.

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0
Area of a square is s^2 22^2= 484 cm^2 is the area of the canvas hope this helps
Nikitich [7]3 years ago
4 0
If we know that Laura's canvas is square, and one side is 22cm,

area of a square is l*w, with a special case of l=w

 the area will be
A= l*w=22*22=484cm^2

also, Asquare is=l^2
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Find the coordinates of the missing endpoint if M is the midpoint of DF <br> F(2,9) M(-1,6)
Hunter-Best [27]

Answer:

(-4,3)

Step-by-step explanation:

6 0
3 years ago
Choose the correct simplification of (6x3 − 7x − 4) + (4x3 + 8x + 3). (5 points)
AleksAgata [21]

i'm pretty sure it's 10x^3 + x - 1

hope this helps

8 0
3 years ago
Determine which statements are true in the set of real numbers3. (Select all that apply.) (a) Two lines parallel to a third line
sashaice [31]

Answer:

(a) True

(b) False

(c) True

(d) False

(e) False

(f) True

(g) False

(h) True

(i) True

(k) True

Step-by-step explanation:

(a) Two lines parallel to a third line are parallel

True

(b) Two lines perpendicular to a third line are parallel

Only for  lines on the same plane

Therefore, false

(c) Two planes parallel to a third plane are parallel

True

(d) Two planes perpendicular to a third plane are parallel

The two planes can be at an angle to each other and so intersect

Therefore, false

(e) Two lines parallel to a plane are parallel

Where the two lines are on a plane parallel to the first plane but the lines are not themselves parallel to each other they intersect

Therefore, false

(f) Two lines perpendicular to a plane are parallel

True

(g) Two planes parallel to a line are parallel

Where the planes are not parallel to each other, they will intersect

Therefore, false

(h) Two planes perpendicular to a line are parallel

True

(i) Two planes either intersect or are parallel

True

(k) A plane and a line either intersect or are parallel

True.

4 0
3 years ago
A rectangle is inscribed in a circle of radius r. if the width of the rectangle is x, what is the height of the rectangle?
user100 [1]

The diagonal of length 2r forms the hypotenuse of a right angled triangle with  one leg ( the width of the rectangle) = x. So by Pythagoras:-

(2r)^2 = h^2 + x^2      where h = height of the rectangle

h^2 = 4r^2 - x^2

h =  √ (4r^2 - x^2)     answer

3 0
3 years ago
I know you’re supposed to change the bounds and break up the integral, but for some reason, I can’t get the 44/3. Can someone ex
tatyana61 [14]

First, look for the zeroes of the integrand in the interval [0, 6] :

x² - 6x + 8 = (x - 4) (x - 2) = 0   ⇒   x = 2   and   x = 4

Next, split up [0, 6] into sub-intervals starting at the zeroes we found. Then check the sign of x² - 6x + 8 for some test points in each sub-interval.

• For x in (0, 2), take x = 1. Then

x² - 6x + 8 = 1² - 6•1 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

• For x in (2, 4), take x = 3. Then

x² - 6x + 8 = 3² - 6•3 + 8 = -1 < 0

so x² - 6x + 8 < 0 over this sub-interval.

• For x in (4, 6), take x = 5. Then

x² - 6x + 8 = 5² - 6•5 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

Next, recall the definition of absolute value:

|x| = \begin{cases}x & \text{for }x \ge0 \\ -x & \text{for }x < 0\end{cases}

Then from our previous analysis, this definition tells us that

|x^2 - 6x + 8| = \begin{cases}x^2 - 6x + 8 & \text{for }0

So, in the integral, we have

\displaystyle \int_0^6 |x^2-6x+8| \, dx = \left\{\int_0^2 - \int_2^4 + \int_4^6\right\} (x^2 - 6x + 8) \, dx

Then

\displaystyle \int_0^2 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_0^2 = \frac{20}3 - 0 = \frac{20}3

\displaystyle \int_2^4 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_2^4 = \frac{16}3 - \frac{20}3 = -\frac43

\displaystyle \int_4^6 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_4^6 = 12 - \frac{16}3 = \frac{20}3

and the overall integral would be

20/3 - (-4/3) + 20/3 = 44/3

3 0
3 years ago
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