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3 years ago

laura bought a square canvas to paint a picture of her cat. one side measures 22 centimeters. what is the area of canvas.

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

6 0

Area of a square is s^2 22^2= 484 cm^2 is the area of the canvas hope this helps

Nikitich [7]3 years ago

4 0

If we know that Laura's canvas is square, and one side is 22cm,

area of a square is l*w, with a special case of l=w

the area will be
A= l*w=22*22=484cm^2

also, Asquare is=l^2

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−3x−6+(−1) equivalent

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Step-by-step explanation:

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3 years ago

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3 years ago

Which situation could be represented by the graph?

Ymorist [56]

The correct option which resembles with the given graph is $\fbox{\begin\\\ optionA and optionC\\\end{minispace}}$ .

Further explanation:

From the given graph the it is observed that the interval is $[8,11)$ which is a half open interval or it can be said that it is a half closed interval.

A half closed or a half open interval is an interval in which one end point of the interval is included but the other point is not included.

For example:

In an interval of the form $[a,b)$ the point $a$ is included in the set but the point $b$ is not included in the set.

Similarly, in the interval $[8,11)$ the point $8$ is included in the set but the point $11$ is not included in the set.

In order to determine the correct option which resembles with given graph form interval for each option.

Option A:

As per the statement in option A the age of the student must be at least $8$ years and not more than $11$ years that is the age of the student is either $8$ years or greater than $8$ years and less than $11$ years.

As per the above statement the interval formed is $\fbox{\begin\\\ [8,11)\\\end{minispace}}$ in which $8$ is included in the set and $11$ is not included which means it is a half closed or half opoen interval.

Therefore, $\fbox{\begin\\\ optionA\\\end{minispace}}$ is a correct option.

Option B:

As per the statement in option B the amount of money the babysitter can earn is between $\$8$ and $\$11$ per hour.

As per the above statement the interval formed is $\fbox{\begin\\\ (8,11)\\\end{minispace}}$ in which both of the end points are not included in the set which means that it is an open interval.

Therefore, $\fbox{\begin\\\ optionB\\\end{minispace}}$ is an incorrect option.

Option C:

As per the statement in option C the time required to complete a program in college cannot be less than $8$ hours and the time must be less than $11$ hours.

From the above statement it is concluded that the time required can be $8$ hours or more than $8$ hours but it has to be less than $11$ hours.

So, as per the above the statement the interval formed is $\fbox{\begin\\\ [8,11)\\\end{minispace}}$ .

Therefore, $\fbox{\begin\\\ optionC\\\end{minispace}}$ is a correct option.

Option D:

As per the statement in option D the age of the dogs is either $8$ years old or below $8$ years and age of the dog must be greater than $11$ tears.

As per the above statement the interval formed is $\fbox{\begin\\\ (-\infty,8) \bigcup(11,\infty)\\\end{minispace}}$ .

Therefore, the $\fbox{\begin\\\ optionD\\\end{minispace}}$ is an incorrect option.

So, $\fbox{\begin\\\ optionA and optionC\\\end{minispace}}$ are the correct options which resembles with the given graph.

Learn more:

A problem on composite function brainly.com/question/2723982
A problem to find radius and center of circle brainly.com/question/9510228
A problem to determine intercepts of a line brainly.com/question/1332667

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Sets

Keywords: Interval, set, open interval, closed interval, half open interval, half closed interval, set theory, program, community college, babysitters, veterinary clinic, ages, students.

5 0

2 years ago

Read 2 more answers

Which of these is a synonym of 'closing sentence"? *

Sophie [7]

Answer:

conclusion because you are concluding eveything you said in the paragraph before.

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3 years ago

Which expression is equivalent to |a|≤3 ?

weqwewe [10]

<h3>Answer: Choice 2. $a \ge -3 \ \text{ and } \ a \le 3$ </h3>

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Explanation:

The rule is that if $|a| \le k$ for some positive number k, then it can be written as the compound inequality $-k \le a \le k$ . This is a shorthand way of writing the two inequalities $a \ge -k \ \text{ and } \ a \le k$ combined together.