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Nesterboy [21]
2 years ago
10

The Surface Area of a square pyramid is 3600 ft2. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot c

ubic blocks can be stuffed in the pyramid?
(*Some of the blocks might have to be cut up to fit into crevices*)
Mathematics
1 answer:
ella [17]2 years ago
4 0

The number of 1 foot cubic blocks that can be stuffed in the pyramid are; 10,583 cubes

<h3>How to find the surface area of a Pyramid?</h3>

The equation for the surface area of a square pyramid is;

Surface area = A + 1/2·p·s

where;

A = area of base

p = perimeter

s = slant height

The volume of the pyramid = (1/3) × A × h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, then there are approximately 10,583 cubes

For rigid cubes we have;

Given that the height of the pyramid = 30·√7

The slope of the pyramid = (30/10)√7 = 3·√7

A increase in height of 1 foot gives a reduction in width of 2/(3√7)

The bottom can hold 400 cubes, Then next layer can hold;

19 × 19 = 361

If we continue to iterate, we will get a total of approximately 9915 rigid cubes in the pyramid.

Read more about Pyramid Surface Area at; brainly.com/question/22744289

#SPJ1

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Pepsi [2]

Answer:

subtraction

Step-by-step explanation:

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3 0
3 years ago
Can someone help with this please
crimeas [40]

Answer:

x2  1-

Step-by-step explanation:

3 0
3 years ago
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Brut [27]
The answer is C I think
4 0
2 years ago
The base of a right pyramid is a regular hexagon with sides of length 12 m. The altitude is 6 m. Find the total surface area of
Eva8 [605]

Answer:

806.12 m

Step-by-step explanation:

<u>Step 1: Write the data</u>

<em>Side (s) = 12</em>

<em>Altitude (h) = 6</em>

<u>Step 2: Write the formula for surface area of right hexagonal pyramid</u>

<em>Area = 3√3/2*s² + 3*s*√(h²+3s²/4)</em>

<u>Step 3: Substitute values of 's' and 'h'</u>

<em>Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]</em>

Area = 806.12 m

Therefore, the total surface area of the pyramid is 806.12 m.

!!

4 0
3 years ago
A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of
Alchen [17]
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.

The value of x is <span>5 feet. </span>

5 0
3 years ago
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