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Nesterboy [21]
1 year ago
10

The Surface Area of a square pyramid is 3600 ft2. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot c

ubic blocks can be stuffed in the pyramid?
(*Some of the blocks might have to be cut up to fit into crevices*)
Mathematics
1 answer:
ella [17]1 year ago
4 0

The number of 1 foot cubic blocks that can be stuffed in the pyramid are; 10,583 cubes

<h3>How to find the surface area of a Pyramid?</h3>

The equation for the surface area of a square pyramid is;

Surface area = A + 1/2·p·s

where;

A = area of base

p = perimeter

s = slant height

The volume of the pyramid = (1/3) × A × h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, then there are approximately 10,583 cubes

For rigid cubes we have;

Given that the height of the pyramid = 30·√7

The slope of the pyramid = (30/10)√7 = 3·√7

A increase in height of 1 foot gives a reduction in width of 2/(3√7)

The bottom can hold 400 cubes, Then next layer can hold;

19 × 19 = 361

If we continue to iterate, we will get a total of approximately 9915 rigid cubes in the pyramid.

Read more about Pyramid Surface Area at; brainly.com/question/22744289

#SPJ1

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How do you do it?I'm lost
Leto [7]

Answer and Step-by-step explanation:

The way you complete this is by taking each points x and y and applying the translation. In this case the translation is x-7 and y+1.

Q's x and y are 1 , 1

R's x and y are 1 , 5

T's x and y are 5 , 1

S's x and y are 5 , 5

Now what you do is use the translation on all of these values.

Q's x and y turns into -6 , 2 (subtracted 7 to the 1 and added 1 to the 1)

R's x and y turns into -6 , 6

T's x and y are -2 , 2

S's x and y are -2 , 6

You can then plot the points on the graph and connect the lines to complete the reflection.

Hope this helps ! !

<3

4 0
3 years ago
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
Read 2 more answers
Please help and explain i will mark brainliesttt!
Art [367]
JIH= QRP
they’re the same shape.
4 0
2 years ago
(- 1/2 + 3/4 ) 1/5
marta [7]
I hope this helps you



(-2/4+3/4).1/5


1/4.1/5


1/20
4 0
2 years ago
Please help!
Alinara [238K]

It is D. ,that one makes the most sense to me

4 0
3 years ago
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