Answer: To be able to create two intersecting arcs above and below the line segment
Step-by-step explanation:
That is one of the steps to bisecting a line segment lol
Answer:
Step-by-step explanation:
From the given right angle triangle,
The hypotenuse of the right angle triangle is 10.
With m∠x as the reference angle,
the adjacent side of the right angle triangle is 6
the opposite side of the right angle triangle is the unknown side.
To determine x, we would apply
the Cosine trigonometric ratio.
Cos θ = adjacent side/hypotenuse. Therefore,
Cosx = 6/10 = 0.6
x = Cos^-1(0.6)
x = 53.1° to the nearest tenth.
Answer:
let ratio 4:5 be 4x& 5x
according to the question
5x=75
x=75/5=15
the number of Maths books=4x=4×5=20 is your answer
10% = 10g/100ml. Ergo, 15ml/100ml (10g) = 1500mg of KCL
.9% NACL = 9g/1000mL, Ergo = 9000mg NaCl
Now we have to figure out how many mEqs of each salt we have.
MW of NaCl = 58.5
MW of KCl = 74.5
So, in moles, we have:
1500 KCl / 74.5 = 20.13 mmol KCl
9000 NaCl / 58.5 = 153.85mmol NaCl
Because the valence of both ions is one, as an example, it would be both 20.13 mEq of Cl- and K+ from 20.13 mmoles of KCL.
So, just add the two together, 20.13 + 153.85 = 174-ish.
