B and C
0+11= +11
0-11= -11
Hope this helps
Answer:
i dont speak spanish
Step-by-step explanation:
Below are the choices that can be found elsewhere:
<span>a. $1,158.33
b. $1,069.23
c. $2,316.66
d. $1,539.22
</span>
Below is the solution:
$27,800 / 12 months = 2,316
$2,316 / 2 since it bi-monthly = $1,158.33
Thank you for posting your question here. I hope the answer helps.
Answer:
(A+B)(A+B)=A.A+B.A+A.B+B.B
Step-by-step explanation:
Given that matrices A and B are nxn matrices
We need to find (A+B)(A+B)
For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.
We know that that in matrices AB is not equal to BA.
Now find
(A+B)(A+B)=A.A+B.A+A.B+B.B
So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.
So (A+B)(A+B)=A.A+B.A+A.B+B.B
Answer: 16p^8q^4r^8 The yellow one
Step-by-step explanation:
Step 1: Use Multiplication Distributive Property: (xy)^a = x^a y^a. So 4^2p^2(q^3)(r^4)^2
Step 2: Simplify 4^2 to 16. So 16p^2(q^3)^2(r^4)^2
Step 3: Use Power Rule: (x^a)^b=x^ab. So 16p^2q^6(r^4)^2
Step 4: Use Power Rule: (x^a)^b=x^ab. So the answer is 16p^2q^6r^8. The yellow one