Answer:
d. 6
Step-by-step explanation:
The product of lengths to the near and far intersection points is the same for both secants:
PB×PA = PD×PC
We can use this relation to solve for x, then use the value of x to find PD.
7×12 = (3x)(7x)
4 = x² . . . . . . . . . divide by 21
2 = x . . . . . . . . . . take the square root
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PD = 3x = 3·2
PD = 6
Answer:
if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.
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Note: sin and cos are complementary functions....
sin(x) = cos (90-x)
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Your Problem:
sin(x-3) = cos(90-(x-3))
Equation:
90-[x-3] = 2x+6
90-x+3 = 2x+6
3x = 93-6
x = 31-2
x = 29
Step-by-step explanation:
Answer:
g o f = 
Step-by-step explanation:
Given
Required:
Find g o f
This is calculated as:
So:
![g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4](https://tex.z-dn.net/?f=g%28f%28x%29%29%20%3D%202%5B%2016x%5E2%20%2B%2016x%20%2B%204%29%5D%20-%204)
Do you need help or you just wanted the answers
Answer: C) Cannot be done
Taking the square root of a negative number is not possible unless you involve complex numbers. If your teacher has not introduced that topic yet, then you just simply say "cannot be done" or something along those lines.
