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3 years ago

What is the value of x, given that PQ||BC?

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

3 0

Answer:

Option D is correct.

Value of x is, 10 units.

Step-by-step explanation:

Triangle Proportionality theorem states that if a line parallel to one side of a triangle intersects the other two sides of a triangle, then the line divide these two sides proportionality.

Given that: $\overline{PQ} || \overline{BC}$

From the given figure, we have;

AP = 3 units , PB = 6 units , QC = 20 units and AQ = x units.

then, by triangle proportionality theorem;

$\frac{AP}{PB} =\frac{AQ}{QC}$

Substitute the given values, to find the value of x;

$\frac{3}{6} =\frac{x}{20}$

By cross multiply we have;

$60 = 6x$

Divide both sides by 6 we get;

10 = x

Therefore, the value of x is, 10 units

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3 years ago

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Doss [256]

Answer:

11. no solution

12. 12, -12.

13. 4/3, -4/3.

14. 6/5, -6/5.

15. 1/2, -1/2.

16. 7/4, -7/4.

Step-by-step explanation:

11. Why it is no solution is when you minus 66 from 3 you get a -63. You then divide 7 by that to get -9. Every time you put a negative inside a square root it will equal no solution every time.

12. 1/2x^2+3=75. I minused the 3 from both sides.

1/2x^2=72. I then times 1/2 to both sides to get 144.

x^2=144. I then square rooted both sides to get 12, -12.

13. 9x^2-16=0. I added 16 to both sides.

9x^2=16. I then divided 9 to both sides.

x^2=16/9. I then square rooted both sides to get 4/3, -4/3.

14. 25x^2+10=46. I minused the 10 from both sides.

25^2=36. I then divided 25 from both sides.

x^2=36/25. I then square rooted both sides to get 6/5, -6/5.

15. 5x^2-1=x^2. I minused x^2 from both sides.

4x^2-1=0. I added 1 to both sides.

4x^2=1. I divided 4 to both sides.

x^2=1/4. I square rooted both sides to get 1/2, -1/2.

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3 years ago

Compute the missing data in the table for the following exponential function . Leave your answer in decimal form.

Snezhnost [94]

Answer: Option C: 0.03125

Step-by-step explanation:

we have an exponential equation, so we have:

f(x) = A*r^x

we have that:

f(1) = A*r^1 = A*r = 0.5

f(2) = A*r^2 = 0.25

f(3) = A*r^3 = 0.125

f(4) = A*r^4 = 0.0625

f(5) = A*r^5 = ?

we want to find the value f(5)

first, let's take the quotient:

f(2)/f(1) = (A*r^2)/(A*r) = r = 0.25/0.5 = 0.5.

then we have:

f(x) = A*0.5^x

and f(1) = A*0.5 = 0.5

then A = 0.5/0.5 = 1.

now we know that our function is f(x) = 0.5^x.

then, if we want to find f(5) we have:

f(5) = 0.5^5 = 0.03125

Then the correct option is option c.

4 0

3 years ago