Six different names were put into a hat. A name is chosen 125 times and the name Grace is chosen 17 times. What is the experimen
tal probability of the name Grace being chosen? What is the theoretical probability of the name Grace being chosen? Use pencil and paper. Explain how each probability would change if the number of names in the hat were different.
Question content area bottom
The experimental probability of choosing the name Grace is __
(Type an integer or a simplified fraction.)
Question content area bottom
The experimental probability of choosing the name Grace is __
(Type an integer or a simplified fraction.)
1 answer:
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Answer: 339/8788= 0.039
Step-by-step explanation:
Let black card be represented with B and the red card be represented with r. Therefore, P(B,r) is the expected value.
Hence, we say, (b,r) is not equal to (0,0) for the first state, we then, have a probability of B/r+B(the probability of drawing out a black card and loosing a point.
Also, (B-1,r) state with the probability of r/r+B(which is the probability of drawing out a red card and gaining a point).
The expected value is therefore;
B/r+B(-1+(B-1,r) + r/r+B(1+P(B,r-1))
Therefore, if we have negative, then;
P(B,r)=0,B/r+B(-1,r)) + r/r+B(1+P(B,r-1))...
P(0,0)=0; P(26,26) = 339/8788
=.039
Note: we say that the expectation at the start if we draw red,gaining +1 and if we draw black and then draw two reds you end +1. That is; 1/26 × 2/26 × 1/26 = 1+ 338/8788
= 339/8788.
