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Elodia [21]
4 years ago
10

Can someone explain me how to find square root by prime factorization ?

Mathematics
1 answer:
liubo4ka [24]4 years ago
5 0

Answer:

<h2><u>STEPS</u></h2>
  • Step I: Obtain the given number.
  • Step II: Resolve the given number into prime factors by successive division.
  • Step III: Make pairs of prime factors such that both the factors in each pair are equal. Since the number is a perfect square, you will be able to make an exact number of pairs of prime factors.
  • Step IV: Take one factor from each pair.
  • Step V: Find the product of factors obtained in step IV.
  • Step VI: The product obtained in step V is the required square root.
<h2><u>Example </u></h2>

<u> Find the square root of 324</u>

  • 324 = 2 x 162
  • = 2 x 2 x 81
  • = 2 x 2 x 3 x 27
  • = 2 x 2 x 3 x 3 x 9
  • = 2 x 2 x 3 x 3 x 3 x 3
  • ∴ √324 = √( 2 x 2 x 3 x 3 x 3 x 3 )
  • √324 = 2 x 3 x 3
  • √324 = 18
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kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed a\leq x \leq b and in your case \nexists x\in\mathbb{Z}: a\leq x\leq b for a>b

In fact, considering a set S we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing $ that satisfy S = S \cup \varnothing

This means that, by definition \sum_{x=a}^b \varnothing = 0

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

we have other problems. Actually, this case is really bad.

Note that \cos^2(\infty) has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$, the cosine function oscillates between [-1, 1] , and therefore it is undefined. Thus, we cannot evaluate

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

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Select the correct values in the table.
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So if it can vary by 75 or less, the least it can be is 1,125 and the greatest it can be is 1275.
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3 years ago
Approximately how much principal would need to be placed into an account earning 3.575% interest compounded quarterly so that it
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<u>Answer-</u>

<em>$23377</em><em> must be deposited to get $68000 at the end of 30 years.</em>

<u>Solution-</u>

We know that for compound interest,

A=P(1+\dfrac{r}{n})^{nt}

Where,

A = Future amount = $68,000

P = ??

r = 3.575% annual = 0.03575

n = 4 as interest is compounded quarterly

t = time in year = 30 years

Putting the values,

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\Rightarrow P=23377.45

Therefore, $23377 must be deposited to get $68000 at the end of 30 years.



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