Question

103^2-102^2=_____×(103-102)=_____pls help me...this is in factorization ​

Answer 1

103^2-102^2  

The property that applies here is a^2-b^2 = (a+b)(a-b)

so the answer is 103^2-102^2=(102+103)*(103-102)= numerically it is 205( as 103+102 = 205 and 103-102 = 1.....so 205*1 = 205)

The thing is that usually the factorization ends at (102+103)(102-103) ......

Answer 2

a² - b² = (a - b)(a + b)

a = 103

b = 102

103² - 102² =

= (103 - 102)(103 + 102)

= 1×205

= 205