103^2-102^2=_____×(103-102)=_____pls help me...this is in factorization
2 answers:
103^2-102^2
The property that applies here is a^2-b^2 = (a+b)(a-b)
so the answer is 103^2-102^2=(102+103)*(103-102)= numerically it is 205( as 103+102 = 205 and 103-102 = 1.....so 205*1 = 205)
The thing is that usually the factorization ends at (102+103)(102-103) ......
a² - b² = (a - b)(a + b)
a = 103
b = 102
103² - 102² =
= (103 - 102)(103 + 102)
= 1×205
= 205
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