Answer:
13 1/3 and 6 2/3.
Step-by-step explanation:
Let the 2 parts be x and (20 - x).
So x^2(20 - x) must be a maximum.
y = x^2(20 - x)
y = 20x^2 - x^3
Finding the derivative):
y' = 40x - 3x^2 = 0 for maxm/minm value.
x( 40 - 3x) = 0
40 - 3x = 0
3x = 40
x = 40/3.
This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.
So the 2 numbers are 13 1/3 and 6 2/3.
9514 1404 393
Answer:
6x^2 +x -12
Step-by-step explanation:
Substitute for A and B and collect terms.
2B +3A
= 2(3x^2 -x +3) +3(x -6) . . . . substitute for A and B
= 6x^2 -2x +6 +3x -18 . . . . . eliminate parentheses
= 6x^2 +x -12 . . . . . . . . . . . . collect terms
Answer:
-6.134 to +6.134
Step-by-step explanation:
given that a large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and a normal distribution
X is Normal with mean =6.1 and std dev = 1 unit
We are to determine the range of values containing 70% of the population of x
We know that normal distribution curve is bell shaped symmetrical about the mean.
So to find 70% range we can use 35% on either side of the mean
Using std normal distribution table the value of z for which probability from 0 to z is 0.35 is 1.034
Hence corresponding x value is
i.e. 70% values lie between
-6.134 to +6.134
Answer:
15 months
Step-by-step explanation:
35x+20=545
Subtract 20 from both side to figure out how many months he paid for....
35x+20-20=545-20
35x=525
Divide 35 on both sides....
x=15
Therefore, he has been a member for 15 months
Check:
35(15)+20=545
525+20=545
545=545
IT'S CORRECT!!!
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