3 years ago

Hi, i really need help! Look at the images below: (there is 2 images per question)

Mathematics

1 answer:

ycow [4]3 years ago

7 0

Answer:

The last one

Step-by-step explanation:

The triangle is simply reflected across the x-axis, so the side lengths and angle measures do not change.

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Put these numbers from least to greatest value. 22/7 , square root of 3, 16/4, square root of 5

Crank

From least to greatest is square root of 3, square root of 5, 22/7 , 16/4
hope it help

8 0

3 years ago

In 2002, the temperature on the first day of summer was 79°F. This is 4°F less than it was on the first day of summer the previo

kap26 [50]

Answer:

C. In 2001, the temperature was 83°F.

Step-by-step explanation:

79 is 4 less than 83.

The temperature in 2001 was 83 °F.

5 0

3 years ago

A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mil

mafiozo [28]

Answer:

The answer is "0.45385".

Step-by-step explanation:

The time is taken to reach the coast $= \frac{\sqrt{(2^2 + x^2)}}{4}$

The time is taken to reach Q after reaching the coast $= \frac{\sqrt{(1 + (3-x)^2)}}{4}$

Total time, $T= \frac{\sqrt{(1 + (3-x)^2)}}{4}+ \frac{\sqrt{(1 + (3-x)^2)}}{4}$

This has to be minimum,

$\to \frac{dt}{dx} = 0$

$\to \frac{\sqrt{(2^2 + x^2)}}{2} + \frac{\sqrt{1 + (3-x)^2}}{3}\\\\ \frac{x}{4}\sqrt{(4+x^2)} + \frac{(x-3)}{(4\sqrt{(x^2-6x+10)}} = 0\\\\\frac{x^2}{16} \times (4+x^2) = \frac{(x-3)^2}{16 \times (x^2-6x+10)}\\\\x^2(4+x^2) = \frac{(x-3)^2}{(x^2-6x+10)}\\\\4x^2+x^4 = \frac{ x^2+9-6x}{(x^2-6x+10)}\\\\ 4x^2+x^4(x^2-6x+10) = x^2+9-6x\\\\4x^4-24x^3+40x^2+x^6-6x^5+10x^4= x^2+9-6x\\\\x^6-6x^5+ 14x^4-24x^3+39x^2+6x-9=0\\\\$