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schepotkina [342]

3 years ago

13

Marie ordered a root beer float at the ice cream shop. the float was $2, and she paid a 6% sales tax. how much did Marie pay for

her root beer float in all?

1 answer:

podryga [215]3 years ago

7 0

$2 (0.06)= 0.12
1
2.00+0.12= 2.12

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mina [271]

Answer:

1)x=15

2)x=38

3)x=7

4)x=10

Step-by-step explanation:

3 0

3 years ago

Can anyone help me with this?

-Dominant- [34]

A=60
B=52
C=152
I’ve attached my work on how I got these answers
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7 0

3 years ago

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In the given figure, mWY = 76° and mXZ = 112. What is the difference of the measures of angle WPY and angle XPY?

skelet666 [1.2K]

Please consider the attached image for complete question.

We have been given that measure of arc WY is 76° and and measure of arc XZ is 112°. We are asked to find the difference of of the measures of angle WPY and angle XPY.

First of all we will find the measure of angle WPY using intersecting secants theorem. Intersecting secants theorem states that measure of angle formed by two intersecting secants inside a circle is half the sum of intercepting arcs.

$m\angle WPY=\frac{1}{2}(\widehat{WY}+\widehat{XZ})$

$m\angle WPY=\frac{1}{2}(76^{\circ}+112^{\circ})$

$m\angle WPY=\frac{1}{2}(188^{\circ})$

$m\angle WPY=94^{\circ}$

We can see that angle WPY and angle XPY are linear angles, so they will add up-to 180 degrees.

$m\angle WPY+m\angle XPY=180^{\circ}$

$94^{\circ}+m\angle XPY=180^{\circ}$

$94^{\circ}-94^{\circ}+m\angle XPY=180^{\circ}-94^{\circ}$

$m\angle XPY=86^{\circ}$

Now we need to find difference of both angles as:

$m\angle WPY-m\angle XPY=94^{\circ}-86^{\circ}$

$m\angle WPY-m\angle XPY=8^{\circ}$

Therefore, the difference of the measures of angle WPY and angle XPY is 8 degrees.

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3 years ago

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PLEASE HELP!! WILL GIVE 200 POINTS PLUS BRAINLY!!!

lisov135 [29]

brainly.com/question/11874728 here is the answer! pls give brainliest

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3 years ago

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The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0

4 years ago