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bazaltina [42]
3 years ago
12

What is the answer to x2 = 121.

Mathematics
2 answers:
algol133 years ago
6 0

Step-by-step explanation: A common mistake in this problem would be to say that if x² = 121, x must equal 11.

However, you must set the equation equal to 0 first.

So our first step is to subtract 121 from both sides to get x² - 121 = 0.

Next, factor the left side to get (x + 11)(x - 11) = 0

So either x + 11 = 0 or x - 11 = 0.

Solving each equation from here, we find that x = -11 or x = 11.

So our answer is not just 11, it's {11, -11}.

jolli1 [7]3 years ago
5 0

Answer:

11 if you mean x^2

Step-by-step explanation:

Since we are solving for x, we need to just get x by its self. The only thing we have to do is get rid of the exponent of (^2). to do this, we have to take teh square root of both sides:

The square root of x^2 is x

The square root of 121 is 11

So the asnwer is x = 11

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3t + 15 = 45. solve pls​
Talja [164]

Answer:

t=10

Step-by-step explanation:

3t + 15 = 45

3t = 30

t = 10

8 0
3 years ago
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The length of the base of an isosceles triangle is x. The length of a leg is 4x-6. The perimeter of the triangle is 96. Find x.
slava [35]

Answer:

12 units

Step-by-step explanation:

base is x

one of the legs measure 4x-6

therefore, perimeter is equal to

2 (4x - 6) + x = 96

8x - 12 + x = 96

9x = 96 + 12

9x = 108

x = 108/9 = 12 units

5 0
3 years ago
There are 172 South American animals in the Springdale zoo. That is 45 more than half the number of african animals in the zoo.
patriot [66]
N=number of African animals in the zoo;
we suggest this equation:
172=45+n/2
Least common multiple=2
172*2=45*2+n
344=90+n
n=344-90
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Answer: there are 254 African animals in the zoo.
6 0
3 years ago
What is the domain of the equation y = 2/5x - 4?
zepelin [54]

Answer:

domain= {x/x€R/x≠0}

Step-by-step explanation:

8 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
uysha [10]

Answer:

(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743

(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926

And we are 9% confidence that the true mean for the difference of the population means is given by:

0.0743 \leq \mu_1 -\mu_2 \leq 1.926

Step-by-step explanation:

For this problem we have the following data given:

\bar X_1 = 9 represent the sample mean for one of the departments

\bar X_2 = 8 represent the sample mean for the other department

n_1 = 25 represent the sample size for the first group

n_2 = 20 represent the sample size for the second group

s_1 = 2 represent the deviation for the first group

s_2 =1 represent the deviation for the second group

Confidence interval

The confidence interval for the difference in the true means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

The confidence given is 95% or 9.5, then the significance level is \alpha=0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df=n_1 +n_2 -2= 20+25-2= 43

And the critical value for this case is t_{\alpha/2}=2.02

And replacing we got:

(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743

(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926

And we are 9% confidence that the true mean for the difference of the population means is given by:

0.0743 \leq \mu_1 -\mu_2 \leq 1.926

4 0
3 years ago
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