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Delicious77 [7]
3 years ago
8

A system of shared beliefs, conventions, norms, behaviors, expectations, and symbolic representations is the definition of _____

_____.
Computers and Technology
1 answer:
Daniel [21]3 years ago
7 0

Answer:

The correct answer to the following question will be "Culture".

Explanation:

  • Organizational culture is a network of common values & attitudes which defines and dictates the actions of its participants within an organization.
  • It consists of an organization's standards, principles, and standards of conduct as well as patterns, goals, interests and behavioral practices of management.

Therefore, Culture will be the right answer.

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When we query for DNS, end user need to see the positive reply from list of servers. Possible for scanning the IPV6 address across the domains and find as positive or negative response. End user has to decide the primary and secondary domain controller’s

Normally secondary domain controller’s as to be configured as standard alone. On success on deciding primary and secondary domain controller’s automate the process from primary to secondary by configuration with ns records. Possible for domain partition also.

8 0
3 years ago
A student is taking a computer course in which there will be four​ tests, each worth 100 points. The student has scores of 92​,
MissTica

Answer:

He must score 86 or more in the fourth test to get and A

Explanation:

The needed score can be found with this equation

(92+88+94+x) = 360

274 + x =360

x = 360 - 274

= 86

x represents the fourth score, the sum of the four scores must be up-to 360 for the student to get an A

7 0
3 years ago
______ is used to ensure that data is organized most efficiently in a database. A) Consistency checking. B) Validation C) Normal
Leya [2.2K]

Answer:

C) Normalization

Explanation:

Normalization is an approach that is to be done in a systematic manner in order to remove the data duplicity and there are non-desirable attributes such as insert, update, delete, etc. In this the process should be followed in multi step that contains the data in a tabular form so that it could eliminate the repetition of data to maintain the efficiency of the data

Therefore according to the given situation, the option C is correct

6 0
3 years ago
In MS Excel, a function is written as =FUNCTION_NAME(_____________________).​
otez555 [7]

Explanation:

A function is a predefined formula that performs calculations using specific values in a particular order. All spreadsheet programs include common functions that can be used for quickly finding the sum, average, count, maximum value, and minimum value for a range of cells. In order to use functions correctly, you'll need to understand the different parts of a function and how to create arguments to calculate values and cell references.

6 0
3 years ago
Write a removeDuplicates() method for the LinkedList class we saw in lecture. The method will remove all duplicate elements from
oksano4ka [1.4K]

Answer:

removeDuplicates() function:-

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

     

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       

       //make ptr1 equals to head.

       ptr1 = head;

        //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

               

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

Explanation:

Complete Code:-

//Create Linked List Class.

class LinkedList {

       //Create head pointer.

       static ListNode head;

       //define structure of ListNode.

       //it has int val(data) and pointer to ListNode i.e, next.

   static class ListNode {

       int val;

       ListNode next;

       //constructor to  create and initialize a node.

       ListNode(int d) {

               val = d;

           next = null;

       }

   }

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       

       //make ptr1 equals to head.

       ptr1 = head;

       

       

       //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

               

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

   //display() function prints linked list.

   void display(ListNode node)

   {

       //run while loop till last node.

       while (node != null)

       {

               //print node value of current node.

           System.out.print(node.val + " ");

           

           //move node pointer by one node.

           node = node.next;

       }

   }

   public static void main(String[] args) {

       

       //Create object of Linked List class.

       LinkedList list = new LinkedList();

       

       //first we create nodes and connect them to form a linked list.

       //Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.

       

       //Create a Node having node data = 1 and assign head pointer to it.

       //As head is listNode of static type. so, we call head pointer using class Name instead of object name.

       LinkedList.head = new ListNode(1);

       

       //Create a Node having node data = 2 and assign head.next to it.

       LinkedList.head.next = new ListNode(2);

       LinkedList.head.next.next = new ListNode(3);

       LinkedList.head.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next = new ListNode(4);

       LinkedList.head.next.next.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next.next.next = new ListNode(5);

       LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);

       //display linked list before Removing duplicates.

       System.out.println("Linked List before removing duplicates : ");

       list.display(head);

       //call removeDuplicates() function to remove duplicates from linked list.

       list.removeDuplicates();

       System.out.println("")

       //display linked list after Removing duplicates.

       System.out.println("Linked List after removing duplicates :  ");

       list.display(head);

   }

}

Output:-

6 0
3 years ago
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