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Irina18 [472]
3 years ago
10

Which of the following is the java comparison operator for "not equal to"

Computers and Technology
1 answer:
Sveta_85 [38]3 years ago
8 0
You need to provide "the following", otherwise other users cannot answer your question.

However, the Java operator for "not equal to" is "!=".


// For example.
if (1 != 2) {
    System.out.println("1 doesn't equal 2");
}


The if-statement in the code above will always run, since 1 is not equal to 2.
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Greg works for an online games development company. He is not a net freak, but occasionally he visits online literature sites an
sweet-ann [11.9K]

Answer:

i think its A

Explanation:i hope i helped

5 0
3 years ago
In this exercise, first run the code as it is given to see the intended output. Then trace through each of the 3 variables to se
dlinn [17]

Answer:

The memory with variable names str1, str2, and str3 all have equal and the same value after the first if-statement.

Explanation:

The str1 was first assigned a null value while the str2 and str3 were assigned the string value "Karen" with the String class and directly respectively. On the first if-statement, the condition checks if the str1 is null and assigns the value of the variable str2 to str1, then the other conditional statement compares the values of all the string variables.

3 0
3 years ago
four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,
marshall27 [118]

Answer:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2

Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

  • 1s² 2s² 2p⁶ 3s² 3p⁶   : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

  • n = 3

  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
  • (3, 1, -1, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
5 0
3 years ago
C++
Cerrena [4.2K]

Answer:

#include <iostream>

#include<iomanip>

using namespace std;

double DrivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)

{

  double dollarCost = 0;

  dollarCost = (dollarsPerGallon * drivenMiles) / milesPerGallon;

  return dollarCost;

}

int main()

{

  double miles = 0;

  double dollars = 0;

  cout << "Enter miles per Gallon   : ";

  cin >> miles;

  cout << "Enter dollars per Gallon: ";

  cin >> dollars;

  cout << fixed << setprecision(2);

  cout << endl;

  cout << "Gas cost for 10 miles : " << DrivingCost(10, miles, dollars) << endl;

  cout << "Gas cost for 50 miles : " <<DrivingCost(50, miles, dollars) << endl;

  cout << "Gas cost for 400 miles: "<<DrivingCost(400, miles, dollars) << endl;

  return 0;

}

Explanation:

  • Create a method definition of DrivingCost that accepts  three input double data type parameters drivenMiles,  milesPerGallon, and dollarsPerGallon and returns  the dollar cost to drive those miles .
  • Calculate total dollar cost and store in the variable, dollarCost .
  • Prompt and read the miles and dollars per gallon  as input from the user .
  • Call the DrivingCost function three times  for the output to the gas cost for 10 miles,  50 miles, and 400 miles.

 

4 0
3 years ago
Read 2 more answers
Don't Answer If You Are Going To Give Me a Link! DON'T WASTE MY POINTS!
dimulka [17.4K]

Answer:

B but don't be surprised if it is not the answer given.  It's just the best of a bunch of poor choices.

Explanation:

This is actually not an easy question to answer. It's one of those answers that has elements of "Some do and Some don't" in them.

A:  is not true for painters and it is not necessarily true for C for painters.

D: photographer can pose his subjects. A painter can pose someone, but not always.

C: Answered under A.

I think the answer you are forced to choose is B, but neither one has to do it. Still life painters ( a bowl of fruit, a bouquet of flowers) and photographs pose the subjects carefully and do not want the fruit or flowers to move around.

I'd pick B, but it does not have to be the answer. I just think it is less wrong than the others.

5 0
3 years ago
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