Answer:
It's
A. Debugging tools help programmers catch errors they might otherwise miss.
B. Debugging tools can save time.
D. Debugging tools help programmers make methodical assessments of the problem.
Explanation:
got it right on edge.
Answer:
B. Virtual reality
Explanation:
In a virtual reality context, the visual and auditory senses of the user are fed by data (images, sounds) from the computer using a goggle and earphones. That allows the person to be totally cut off her real physical environment and be totally immersed into the world (reality) managed by the computer.
Not to be confused with<u> augmented reality</u>, where the physical reality and perception of it aren't changed... but an additional layer of information is added on top of it. Like pointing your phone camera to a building and getting information about the building displayed on your phone.
Answer:
11. 1million square decimetres (from online)
20. assuming room is rectangular,
length= (p - 2b)/2
because perimeter= 2 length + 2 breadth for rectangular
Answer:
The solution code is written in C++
- float cellPhone(int m, int tx){
- float COST_PER_MIN = 0.1;
- float COST_PER_MESSAGE = 0.2;
-
- float bill_amount = m * COST_PER_MIN + tx * COST_PER_MESSAGE;
-
- return bill_amount;
- }
Explanation:
Firstly, declare a function named cellPhone() that takes two input parameters, m and tx (Line 1).
Since the policy of the carrier company is not given in the question, I make a presumption that the cost per minutes is $0.10 and the cost per message is $0.20 (Line 2- 3).
Next, apply the formula m * COST_PER_MIN + tx * COST_PER_MESSAGE to calculate the total bill (Line 5) and return the bill_amount as function output (Line 7).
Answer:
C++.
Explanation:
<em>Code snippet.</em>
#include <map>
#include <iterator>
cin<<N;
cout<<endl;
/////////////////////////////////////////////////
map<string, string> contacts;
string name, number;
for (int i = 0; i < N; i++) {
cin<<name;
cin<<number;
cout<<endl;
contacts.insert(pair<string, string> (name, number));
}
/////////////////////////////////////////////////////////////////////
map<string, string>::iterator it = contacts.begin();
while (it != contacts.end()) {
name= it->first;
number = it->second;
cout<<word<<" : "<< count<<endl;
it++;
}
/////////////////////////////////////////////////////////////////////////////////////////////////////////
I have used a C++ data structure or collection called Maps for the solution to the question.
Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.
