Not entirely sure about 1; I believe it's D. 2 is C, and 3 is A.
The main aim of running the parameters in the linear perceptron algorithm is to be able to develop a machine learning algorithm for binary classification tasks.
<h3>What is a linear perceptron algorithm?</h3>
This refers to the linear classification algorithm that is used in machine learning.
This is done in order to learn a decision boundary that divides different classes using a hyperplane.
Hence, we can see that your question is incomplete because the parameters are not included, hence a general overview was given to give you a better understanding of the concept.
Read more about machine learning here:
brainly.com/question/25523571
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Answer: No, because all you need is WiFi for both devices and a messaging app to do it for free like iMessage.
Explanation: Please correct me if I am wrong! :)
Answer:
public static String repeat(String text, int repeatCount) {
if(repeatCount < 0) {
throw new IllegalArgumentException("repeat count should be either 0 or a positive value");
}
if(repeatCount == 0) {
return "";
} else {
return text + repeat(text, repeatCount-1);
}
}
Explanation:
Here repeatCount is an int value.
at first we will check if repeatCount is non negative number and if it is code will throw exception.
If the value is 0 then we will return ""
If the value is >0 then recursive function is called again untill the repeatCount value is 0.
Answer:
Explanation:
The following code is written in Java and runs a thread every 45 seconds that adds the two counters together and saves them in an integer variable called register. Then prints the variable. If this code runs 5 times it automatically breaks the loop. This can be changed or removed by removing the breakLoopCounter variable.
public static void add_Counters(int counterOne, int counterTwo) {
int register = 0;
int breakLoopCounter = 0;
try {
while (true) {
register += counterOne + counterTwo;
System.out.println(register);
Thread.sleep(45000);
breakLoopCounter += 1;
if (breakLoopCounter == 5) {
break;
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
