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goldfiish [28.3K]
2 years ago
5

Bored can you talk to me

Computers and Technology
2 answers:
Sedaia [141]2 years ago
7 0
Uhhhhh got any hobbies?
Vedmedyk [2.9K]2 years ago
4 0

Answer:

yeppppppppp.........

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Difference between multiterm access and single term access for webassign
NemiM [27]

The difference between single term access and multi term access is that multi-term access is for more than one term to courses using the same textbook edition and the Single term access<span> lasts for the duration of a Single  course in Web Assign. </span>

Multi-term access is also known as "Lifetime of Edition"

<span />
4 0
3 years ago
Which computer can be used where there is no regular electricity?​
alina1380 [7]

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A mechanical computer

Explanation:

Created from gears and levers

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2 years ago
g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err
grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

   

   // variables declared

   int n;

   int sum=0;

   float avg;

   

   do

   {

       // user input taken for number    

       cout<< "Enter a number between 1 and 100 (inclusive): ";

       cin>>n;

       

       if(n<1 || n>100)

           cout<<" Number is out of range. Enter valid number."<<endl;

       

   }while(n<1 || n>100);

   

   cout<<" "<<endl;

   

   // printing even numbers between num and 50  

   for(int num=1; num<=n; num++)

   {

       sum = sum + num;

   }

   

   avg = sum/n;

   

   // displaying sum and average

   cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

   cout<<"Average of numbers between 1 and "<<n<<" is ";

   printf("%.2f", avg);

   

       return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

 

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0
3 years ago
Using functions,
ZanzabumX [31]

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

int main()

{

double h, w;

int s, a, b;

cout<<"height in feet: ";

cin>>h;

cout<<"width in feet: " ;

cin>>w;

cout<<"tile size in inches:";

cin>>s;

int height = h*12;

if(height%s==0)

a = height/s;

else

a = height/s + 1;

int width = w*12;

if(width%s==0)

b = width/s;

else

b = width/s + 1;

cout<<"Number of tiles: "<<a*b;

}

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