<h2>
Answer:</h2>
1)
PART-A Perimeter= 24 in.
PART-B Area of inside frame=6×4=24 square inches.
2)
4) Dimensions of outside frame= 12.5 ft×17.5 ft.
<h2>
Step-by-step explanation:</h2>
1)
PART-A
the outside frame has the measures as: 7 in. and 5 in.
i.e. the frame is in shape of a rectangle.
Perimeter of the outside edge= 7+7+5+5=14+10=24 in.
Hence, Perimeter= 24 in.
PART-B
Now we are asked to find the area of the inside of a frame as the frame is in the shape of a rectangle.
We know that the area of rectangle= l×b
where l represents the length of the frame and b represents the breadth of the rectangle.
Here we have l=6 in.
and b=4 in.
Hence, Area of inside frame=6×4=24 square inches.
2)
Now we are given that the area of the frame was 64 inches².
So the possible dimensions could be:
4)
Now we are using a scale factor as:
1 in.=2.5 ft.
the dimension of the outside frame was: 5 in.×7 in.
As 1 in.=2.5 ft.
5 in.=5×2.5=12.5 ft.
and 7 in.=7×2.5=17.5 ft.
Hence, the new dimension after using the scale factor is:
12.5 ft×17.5 ft.