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BlackZzzverrR [31]
3 years ago
10

Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0
f(x)=x^2+6x+3

Complete the square:

x^2+6x+a^2\implies a=\dfrac{6x}{2x}=3\implies x^2+6x+3^3

And we have:

f(x)=x^2+6x+3\\\\f(x)=x^2+6x+3^2-3^2+3\\\\f(x)=(x+3)^2-9+3\\\\\boxed{f(x)=(x+3)^2-6}

Answer B.

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Find the area of a segment of a circle if its arc is 120 degrees and the radius is 3 inches.
Montano1993 [528]

Answer:<u> 9.42 inches</u>, 3π in terms of pi

Step-by-step explanation:

A full circle is 360 degrees, so if the segment has an arc of 120 degrees, it is 1/3 of a regular circle.

To find the area of a circle, we use the equation A = πr^2. In this case, we will divide the equation by 3 because we are only finding 1/ of a circle. So, our equation will be A  = (πr^2)/3.

Using 3.14 for π:

A  = (πr^2)/3.

A = (π3^2)/3

A = (π9)/3

A = 3π

A = 9.42

6 0
1 year ago
What are two ways that you can find the surface area of a prism
3241004551 [841]

Answer:


Step-by-step explanation:


4 0
3 years ago
Compare the functions.
marshall27 [118]

Function h has the largest y-intercept which is 44

Step-by-step explanation:

Any linear function is represented in the form

f(x) = mx+b

Here b is the y-intercept of the linear function i.e. the constant term in the function.

We will compare all the functions with the general form we get

y-intercept of f(x) = 1

y-intercept of g(x) = 8

y-intercept of h(x) = 44

y-intercept of j(x) = 0

Hence,

Function h has the largest y-intercept which is 44

Keywords: intercepts, linear functions

Learn more about intercepts at:

  • brainly.com/question/9532142
  • brainly.com/question/9590016

#LearnwithBrainly

5 0
2 years ago
Complete the scale by labeling the remaining tick marks​
scoundrel [369]

Answer:

Can you provide a picture?

I cannot help you if you don't.

5 0
2 years ago
What is the value of (7 + 2i)(3 - i)?
Harrizon [31]
There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}

Imaginary numbers:
Using the result from earlier:
21-i-2i^{2}
Now since i = \sqrt{-1}, then the expression becomes:
21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i
7 0
3 years ago
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