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3 years ago

Which function in vertex form is equivalent to f(x) = x^2 + 6x + 3?

1 answer:

3 0

$f(x)=x^2+6x+3$

Complete the square:

$x^2+6x+a^2\implies a=\dfrac{6x}{2x}=3\implies x^2+6x+3^3$

And we have:

$f(x)=x^2+6x+3\\\\f(x)=x^2+6x+3^2-3^2+3\\\\f(x)=(x+3)^2-9+3\\\\\boxed{f(x)=(x+3)^2-6}$

Answer B.

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zvonat [6]

Given:

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To find:

The length of missing side JK.

Solution:

LJ = k = 89

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JK = l = ?

Using law of cosine:

$l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L$

Substitute the given values.

$l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ$

$l^{2}=784+7921-4984 \cdot (0.7)$

$l^{2}=784+7921-4984 \cdot (0.7431)$

$l^{2}=784+7921-3703.6$

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Taking square root on both sides.

$l=70.7$

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3 years ago

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nikklg [1K]

Answer:

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2 years ago

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Given A(3, 4), B(4, 3) and C(2, 1), what are the coordinates of C', the image of C under a rotation of 90 degrees about the orig

Aleks [24]

<u>Given</u>:

The coordinates of the points A, B and C are (3,4), (4,3) and (2,1)

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<u>Coordinates of the point C':</u>

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Answer:

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