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4 years ago

There are 8 pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?

2 answers:

Volgvan4 years ago

8 0

To find this answer, you must first figure out how any pencils you are going to need.
so to find that you must multiply the number of children by the number of pencils each person will use. So 28 x 4 = 112
So then you have to figure out how many packages that you will need.
so to do that you divide the number of pencils by the number of pencils in one package.
so 112 / 8 = 14
The answer is 14 packages.
I hope this helps!
Have an amazing day!

yanalaym [24]4 years ago

3 0

14 packages will be needed for 28 children

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You sight the top of a 50-ft tree from a point on the ground 50 ft from the base of the tree. What is the angle of elevation?

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Answer:

Step-by-step explanation:

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3 years ago

Translate the following points 5 units up (-5,-2) (-2,1) (-4,-7)

kobusy [5.1K]

Answer:
(-5, 3)
(-2, 6)
(-4, -2)

Explanation:
To translate 5 units up means to add 5 to the y value since the y-axis dictates the vertical positioning of a coordinate. However, the x-values remain unchanged.
So all the y values are -2, 1, and -7. Add 5 to all of these.
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1 + 5 = 6
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Then re-pair them with their x-values like so:
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3 years ago

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3 years ago

Write the number 31 in tens and ones. 2 tens

sammy [17]

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4 years ago

Read 2 more answers

Consider estimating a population proportion p. What is the most conservative sample size (erring on the large size) required in

just olya [345]

Answer:

The most conservative sample size is 2401.

Step-by-step explanation:

We are given the following in the question:

We are not given any approximation of s]ample proportion, thus,

$\hat{p} = 0.5$

We have to construct a 95% confidence interval.

Margin of error = 2% = 0.02

Formula for margin of error =

$z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get,

$0.02 = 1.96\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\0.02 = 1.96\times \sqrt{\dfrac{0.5(1-0.5)}{n}}\\\\\sqrt{n} = 1.96\times \dfrac{\sqrt{0.5(1-0.5)}}{0.02}\\\\\sqrt{n}=49\\n = 2401$

Thus, the most conservative sample size is 2401.

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3 years ago