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3241004551 [841]
3 years ago
12

State the x- and y-intercepts of each equation. Then use the intercepts to graph the equation. y= 3x-9

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0
The x- intercept is 3 and the y- intercept would be -9
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You just took out a $200,000 mortgage. You must make equal monthly payments over 30 years, and your interest rate is 6% APR. Wha
Vesnalui [34]

Answer:

  a)  $1199.10

  b)  interest: $1000.00

  c)  principal: $199.10

Step-by-step explanation:

a) The monthly payment can be found using a financial calculator or using the amortization formula:

  A = P(r/12)/(1 -(1+r/12)^(-12t))

for Principal P, annual interest rate r, and time t years.

Filling in the given values and doing the arithmetic yields ...

  A = $200,000(0.06/12)/(1 -(1+0.06/12)^(-12·30)) = 1000/(1 -1.005^-360)

  A ≈ $1199.10

__

b) The first month's interest is the monthly interest rate times the initial loan balance:

  = (0.06/12)·(200,000) = 1000.00 . . . . dollars in interest

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c) The first month's payment to principal is the difference between the payment amount and the amount to interest:

  $1199.10 -1000 = $199.10 . . . . . first month's payment on principal

7 0
3 years ago
Estimate 5÷10/11 to the nearest whole number
4vir4ik [10]

Answer:

{ \tt{5 \div  \frac{10}{11} }} \\  \\  \dashrightarrow \: { \tt{5 \times  \frac{11}{10} }} \\  \\ \dashrightarrow \: { \tt{ \frac{55}{10}  = 5.5}} \\  \\ \dashrightarrow \: { \boxed{ \tt{ 5 \div  \frac{10}{11}  \approx \: 6}}}

3 0
3 years ago
Read 2 more answers
What are the solutions to the equation x squared + x -30 =12
statuscvo [17]

Answer:

x = 6   x = -7

Step-by-step explanation:

Subtract 12 from each side:

x^2 + x - 30 - 12 = 12 - 12

Simplify:

x^2 + x - 42 = 0

Solve with quadratic formula using both +/- after the first -1:

x = \frac{-1+\sqrt{1^2 -4*1(-42)} }{2*1}

Simplify:

x = 6

x = -7

3 0
3 years ago
The line for which equation has a negative slope?
grandymaker [24]
Final answers
1)b

2)b

your welcome
5 0
3 years ago
if <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B3%7D%20-%20%5Cfrac%7B1%7D%7B2%7Dx%20" id="TexFormula1" title="f
Dimas [21]

Answer:

\large\boxed{(f+g)(x)=2x^2+\dfrac{1}{2}x+4\dfrac{1}{3}}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\\text{We have}\\\\f(x)=\dfrac{1}{3}-\dfrac{1}{2}x,\ g(x)=2x^2+x+4.\\\\\text{Substitute:}\\\\(f+g)(x)=\left(\dfrac{1}{3}-\dfrac{1}{2}x\right)+(2x^2+x+4)\\\\=\dfrac{1}{3}-\dfrac{1}{2}x+2x^2+x+4\qquad\text{combine like terms}\\\\=2x^2+\left(-\dfrac{1}{2}x+x\right)+\left(\dfrac{1}{3}+4\right)\\\\=2x^2+\dfrac{1}{2}x+4\dfrac{1}{3}

6 0
3 years ago
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