Answer: 4y/(y+3)
Explanation:
{(2y)(4y-12)}/{(y-3)(2y+6)}
= (8y^2 - 24y)/(2y^2 + 6y - 6y - 18)
= (8y^2 - 24y)/(2y^2 - 18)
= {8y(y-3)}/{2(y+3)(y-3)}
= 2 * 4y/{2(y+3)}
= 4y/(y+3)
To find the lateral surface area of a pyramid, you can find the area of each triangle, A = 1/2bh or A = 1/2lw, then multiply by the number of triangles, which would be based on the number of sides of the base; or you can take half the perimeter and multiply by the slant height.
Y+3=1/4x-1/4
0.25x-y=3-0.25
0.25x-y=2.75
The grade of her sci test was 61. First I add 37 to 85, the sum being 122. Then if you divide it in half, you get the quotien and final answer of 61