The third quartile of this data set is B. 24.
2x2x2 = 8
4 x 2 x 2 = 16
16+8 = 24
Answer is A
The ball's maximum height is 30.25 feet.
<h3>What is quadratic equation?</h3>
A quadratic equation in math is a second-degree equation of the form ax² + bx + c = 0. Here a, b, are the coefficients, c is the constant term, and x is the variable.
Given:
h= -16t²+36t+10
Differentiate w.r.t. 't',
h' = -32t+36
When h=0, that will be the maximum height
32t= 36
t= 9/8
t= 1.125 sec.
So, The maximum height is
h(1.123)= -16(1.125)² + 36*1.125+10
h(1.125) = 30.25 feet.
Learn more about this concept here:
brainly.com/question/10335037
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See the picture attached to better understand the problem
we know that
in the right triangle ABC
tan 64°=AB/AC------> AB=AC*tan 64°-----> AB=x*tan 64°---> equation 1
in the right triangle ABD
tan 43°=AB/DA----> AB=DA*tan 43°---> AB=(240+x)*tan 43°---> equation 2
equate equation 1 and equation 2
x*tan 64°-=(240+x)*tan 43°---->x*tan 64=240*tan 43+x*tan 43
x*[tan 64-tan 43]=240*tan 43-----> x=240*tan 43/[tan 64-tan 43]
x=200.22 ft
AB=x*tan 64----> AB=200.22*tan 64-----> AB=410.51 ft
the answer is410.51 ft