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scoundrel [369]
3 years ago
8

Consider this system of equation. Which shows the second equation written in slope-intercept form?y = 3x - 210(x+3/5)=2yA) y=5x+

3/10B) y=5x+3C) y=1/5x+3/25D) y=1/2x+6
Mathematics
1 answer:
SashulF [63]3 years ago
7 0

we have that

y = 3x - 2

10(x+3/5)=2y------> the second equation----->divide by 2 both sides

5(x+3/5)=y-----> y=5x+3

y=5x+3------> second equation written in slope-intercept form

so


case A) y=5x+3/10-----> is not equal to y=5x+3

case B) y=5x+3--->is equal to y=5x+3--------->  is the answer

case C) y=1/5x+3/25-------> is not equal to y=5x+3

case D) y=1/2x+6-----> is not equal to y=5x+3


therefore


the answer is the option

B) y=5x+3

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H(t)=-16t^2+15t+12
(e)
maximum height is reached when h'(t)=-32t+15=0, or tm=15/32 seconds.
maximum height reached = h(tm)=h(15/32)=-16(15/32)^2+15(15/32)+12
=993/64 ft
=15.516 ft.
(f) when Greg reaches water, h(t)=0=-16t^2+15t+12
Solve for t using quadratic formula,
t=[-15+/- sqrt(15^2+4*12*16)]/(2*-16)
=-0.516s or 1.4535s.
Reject negative root so
Greg reaches water at t=1.4535 seconds.
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