Question

1. Factor completely: 2a^2 + 6a + 18

Answer 1

Answer:

$2(a+3)(a+3)$

$5(x+1)(x-1)$

$3t(t-2)(t+8)$

$n(2+n)(2-n)$

Step-by-step explanation:

Factor each expression

$2a^2 + 6a + 18$

$2(a^2 + 3a + 9)$

product =9 and sum =6

3 times 3 is 9

3 plus 3 is 6

$2(a+3)(a+3)$

2. Factor completely: 5x^2 − 5

GCF is 5

$5x^2 - 5$

$5(x^2 - 1)$

$5(x+1)(x-1)$

3. Factor completely: 3t^3 + 18t^2 − 48t

$3t^3 + 18t^2 -48t$

$3t(t^2 + 6t -16)$

product is -16 and sum is 6

-2 times 8 = -16

-2+8=6

$3t(t^2 + 6t -16)$

$3t(t-2)(t+8)$

4. Factor completely: 4n − n^3

$n(4 -n^2)$

$n(2+n)(2-n)$