All categories

3 years ago

How do i get a equation that equals 24 using the numbers 8 3 5 and 1 with a 24 card using multiplication negative times division

2 answers:

5 0

First you do 8-3 which =5

Next take that 5 and multiply it by 5

Then it would be 25,last you subtract 1 and that gives you 24

ElenaW [278]3 years ago

3 0

Answer:

[(8-3)×5]-1=24

Step-by-step explanation:

[(8-3)×5]-1=24

[(5)×5]-1=24

[5×5]-1=24

[25]-1=24

25-1=24

24=24

You might be interested in

There are 33 of them altogether and pay £311 in total. How many kids are in the family? Adults pay £15 and kids pay £7

Marrrta [24]

Answer:

Step-by-step explanation

Let x be the number of adults and y the number of kids

We can then write this two equations :

x+y= 33

15x+7y= 311

let's solve the two eaquations

to do that we should combine them both in a way that help us get rid of one of the variables.

Let's multiply the first equation by -7 to get rid of y by adding it to thr second equation

-7x-7y= -231

now add both equations .

15x+7y-7x-7y=311-231

we get : 8x = 80

as you notice y is gone and we get a classic easy equation to solve

x= 80/8

= 10

so the number of adults is 10

let's go back to the first equation ( x+y= 33) and replace x with 10

10+y= 33

y= 33-10

=23

let's check using the second equation :

(10*15)+(23*7) = 311

that is true

so :

the number of adults is 10
the number of kids is 23

4 0

3 years ago

In the book Business Research Methods, Donald R. Cooper and C. William Emory (1995) discuss a manager who wishes to compare the

S_A_V [24]

Answer:

Null hypothesis is: U1 - U2 ≤ 0

Alternative hypothesis is U1 - U2 > 0

Step-by-step explanation:

The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.

Let U1 = mean sales by type A trainees

Let U2 = mean sales by type B trainees

Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0

This implies that type A training does not result in higher mean weekly sales than type B training.

The alternative hypothesis (H1) is: U1 - U2 > 0

This implies that type A training indeed results in higher mean weekly sales than type B training.

4 0

3 years ago

No links or wrong answers please!! 55 points

juin [17]

The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)

<h3>How to determine the total areas?</h3>

<u>The figure 1</u>

In this figure, we have

Length = x + 1

Width = 4

The area is calculated as:

Area = Length * Width

So, we have

Area = 4(x + 1)

<u>The figure 2</u>

In this figure, we have

Length = d + 4

Width = 7

The area is calculated as:

Area = Length * Width

So, we have

Area = 7(d + 4)

<u>The figure 3</u>

In this figure, we have

Length = y + 3

Width = y

The area is calculated as:

Area = Length * Width

So, we have

Area = y(y + 3)

Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)