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3 years ago

Solve for z. z−49−13=59

Mathematics

2 answers:

Delvig [45]3 years ago

6 0

z = 59 +13 + 49 = 121

z = 121

Radda [10]3 years ago

3 0

Answer: The required value of z is 121.

Step-by-step explanation: We are given to solve the following equation for the value of z :

$z-49-13=59~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To solve the given equation for z, we must take all the terms involving z on one side and the constant terms on the other side of the equation.

The solution of equation (i) is as follows :

$z-49-13=59\\\\\Rightarrow z=59+13+49\\\\\Rightarrow z=121.$

Thus, the required value of z is 121.

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3 years ago

Determine all real values of p such that the set of all linear combination of u = (3, p) and v = (1, 2) is all of R2. Justify yo

Rama09 [41]

Answer:

p ∈ IR - {6}

Step-by-step explanation:

The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2

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And also u and v must be linearly independent.

In order to achieve the final condition, we can make a matrix that belongs to $R^{2x2}$ using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.

Let's make the matrix :

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We used the first vector ''u'' as the first column of the matrix A

We used the second vector ''v'' as the second column of the matrix A

The determinant of the matrix ''A'' is

$Det(A)=6-p$

We need this determinant to be different to zero

$6-p\neq 0$

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The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that $p\neq 6$

We can write : p ∈ IR - {6}

Notice that is $p=6$ ⇒

$u=(3,6)$

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4 years ago

The 9th graders are selling tickets to raise money for a class field trip. They are selling student tickets for $5 and adult tic

Marina CMI [18]

Answer:

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Solving equations (1) and (2) using elimination method:

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4 years ago

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Answer:

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3 years ago

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$\begin{gathered} \frac{h}{24}=\frac{4}{6} \\ \text{cross multiply} \\ 6\cdot h=4\cdot24 \\ 6h=96 \\ \text{divide boths} \\ \frac{6h}{6}=\frac{96}{6} \\ h=16 \end{gathered}$

therefore, the heigth of the tree is 16 ft

5 0

1 year ago