Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
The y intercept line represents C. total time spent running
Answer:
- x - 24 = 0
a = 1
b = 1
c = -24
Step-by-step explanation:
(x + 4)(x - 5) = 4
x(x - 5) =
- 5x
4(x - 5) = 4x - 20
- 5x + 4x - 20 = 4
- x - 20 = 4
- x - 20 - 4 = 0
- x - 24 = 0
a = 1
b = 1
c = -24
Answer: where is it?
what do u mean??? im confused...