Question

A line contains the points (−26, −37) and (−32, −61) .

Answer 1

Answer:

4

Step-by-step explanation:

To find the slope you must use the slope formula.

it is y2-y1/x2-x1. with the points (-26,-37) and (-32,-61)

you do -61 minus -37 divided by -32 minus -26. first do -61 minus -37 = -24. then do -32 minus -26 = -6. And -24 divided by -6 = 4. the slope is 4.

Hope this helps. Sorry if its confusing.

Answer 2

Answer:

Slope: 4

Equation: y = 4x + 67

Step-by-step explanation:

• Line mx+b passes through points $\bold{\left(-26,\:-37\right)\mathrm{,\:}\left(-32,\:-61\right)}$

Find Slope (m): $\bold{\frac{y_2-y_1}{x_2-x_1}}$

$\bold{\left(x_1,\:y_1\right)=\left(-26,\:-37\right),\:\left(x_2,\:y_2\right)=\left(-32,\:-61\right)}$

$\bold{m=\frac{-61-\left(-37\right)}{-32-\left(-26\right)}}$

Refine: m = 4

Find y intercept (b): Plug 4 into y=mx+b

y=4x+b

Plug in $\bold{\left(-26,\:-37\right)\mathrm{:\:}\quad \:x=-26,\:y=-37}$

-37 = 4(-36) + b

Solve for b: b = 67

Equation: y = 4x + 67

m: 4

y: 67