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velikii [3]
4 years ago
14

What is the length of the hypotenuse 45 45 90

Mathematics
1 answer:
dmitriy555 [2]4 years ago
3 0

- "In other words, in every 45-45-90 triangle, the lengths of the two legs are always equal, and the ratio of the length of the hypotenuse to the length of a leg is always square root 2 to 1."

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At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T
elixir [45]

Answer:

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

To find the approximate area of side walk let us substitute pi equals 3.14.

\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Therefore, the approximate area of the side walk is 125.6\text{ m}^2.

5 0
3 years ago
Find the volume of a cylinder with a radius of 5 cm and a height of 10 cm. Then, find the volume of the cylinder if the radius i
kap26 [50]

Answer:

250π

1000π

Step-by-step explanation:

(refer to attached)

volume of cylinder is given by:

V = π r²h,

where r = radius of base and h = height of cylinder

Given r = 5 and h = 10, hence

V = π r²h

V = π (5)²(10)

V = π (25) (10)

V = 250π  (answer)

For the second case, r = 10 cm

V = π r²h

V = π (10)²(10)

V = π (100) (10)

V = 1000π  (answer)

3 0
3 years ago
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Step-by-step explanation:

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3 0
3 years ago
Solving systems of equations<br><br> X-2y=0<br> Y=2x-3
bearhunter [10]
\left \{ {{x-2y=0} \atop {y=2x-3}} \right. \\\\Substitute\ second\ equation\ to\ first:\\\\x-2(2x-3)=0\\x-4x+6=0\\-3x=-6\ \ \ \ \ |:-3\\x=2\\\\y=2\cdot2-3\\y=4-3=1\\\\ \left \{ {{y=1} \atop {x=2}} \right.
5 0
4 years ago
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What’s the correct answer for this question?
weqwewe [10]

Answer:

Last answer choice

Step-by-step explanation:

The AAS congruence theorem uses two adjacent angles, followed by a side length on the side (not in between the angles.) Therefore, the first answer is ruled out (because it deals with angles and not sides), and the second answer is ruled out because it involves side lengths between angles. LP=MO may be true, but it does not compare the two triangles that we are interested in. However, the last answer choice is correct, because a midpoint divides a line exactly in half, meaning that both halves are the same length and therefore congruent. Therefore, the last answer choice is correct. Hope this helps!

7 0
3 years ago
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