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Monica [59]
3 years ago
13

Sarah competes in a long jump competition Her first jump is 4.25m Her best jump is 12% more than this However, her best jump is

15% lower than the winning jump Work out the length Of The winning jump
Mathematics
1 answer:
ad-work [718]3 years ago
8 0

>First jump = 4.25 m

 

>Best jump = 1.12 * First jump

Best jump = 1.12 * (4.25 m)

Best jump = 4.76 m

 

>Best jump = 0.85 * Winning jump

Hence,

Winning jump = Best jump / 0.85

Winning jump = 4.76 m / 0.85

<span>Winning jump = 5.6 m</span>

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Answer:

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Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1, - 1) and (x₂, y₂ ) = (6, 2)

d = \sqrt{(6+1)^2+(2+1)^2}

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Anice has $64 left in her checking account. If she writes a check for $87, what
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Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
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