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AveGali [126]
3 years ago
8

A digital video recorder (DVR) records television shows on an internal hard drive. To use a DVR, you need a subscription with a

DVR service company. Two companies advertise their charges for a DVR machine and subscription service.
For what number of months will consumer pay less for the machine and subscription at easy electronics than at cable solutions



The consumer will pay less for the machine and a subscription at easy electronics then I have cable solutions if the customer uses .......... months or more


Will give brainliest

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer: 23.333

Step-by-step explanation:

Look at the photo for explanation and answer

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Match each function with the corresponding function formula when h(x) = 5 - 3x and g(x) = -3 x + 5.
laila [671]

Answer:

To match each functions with the corresponding function formula when h(x) = 5 - 3x and g(x) = -3 x + 5.

1. k(x) = (3h - 5g)(x)

  = = 3(5 - 3x)-5(-3 x + 5)

 = = 15 - 9x + 15x - 25

  K(x) = -10 + 6x

2.  k(x) = (h - g)(x)

    = = (5 - 3x) - (-3 x + 5)

 = = 0

k(x) = 0

3. k(x) = (5g + 3h)(x)

 = = 5(-3 x + 5)+3(5 - 3x)

 = = -15x + 25 + 15 - 9x

 k(x) = - 24x +40

4. k(x) = (3g + 5h)(x)

  =  = 3 (-3 x + 5) + 5(5 - 3x)

 = = -9x + 15 +25 -15x

 k(x) = -24x + 40

5.  k(x) = (g + h)(x)

   = = (-3 x + 5) + (5 - 3x)

k(x)  = -6x + 10

6.  k(x) = (5h - 3g)(x)

 = = 5(5 - 3x) - 3(-3 x + 5)

= =25 - 15x + 9x - 15

k(x) = 10 - 6x

6 0
3 years ago
Could someone help me out?
worty [1.4K]

Since the grade of the numerator and the denominator is the same, then the limit exists and is distinct from 0. The limit of the expression is 4/7.

<h3>How to determine the limit of a rational expression when x tends to infinite</h3>

In this problem we must apply some algebraic handling and some known limits to determine whether the limit exists or not. The limit exists if and only if the result exists.

\lim_{x \to \infty} \frac{4\cdot x - 1}{7\cdot x + 3}

\lim_{x \to \infty} \frac{4\cdot x - 1}{7\cdot x + 3} \cdot \frac{x}{x}

\lim_{x \to \infty} \frac{4 - \frac{1}{x} }{7 + \frac{3}{x} }

\lim_{x \to \infty} \frac{4}{7}

4/7

Since the grade of the numerator and the denominator is the same, then the limit exists and is distinct from 0. The limit of the expression is 4/7.

To learn more on limits: brainly.com/question/12207558

#SPJ1

8 0
2 years ago
Please help me with pythagoras.
lana [24]

Answer:

(q)

cb \:  =  \sqrt{4 {}^{2}  +  {3}^{2} }

cb = 5

q =  \sqrt{ {13}^{2}  -  {5}^{2} }

q = 12

(r)

cb = \sqrt{ {13}^{2} -  {5}^{2}  }

cb = 12

r =  \sqrt{12 {}^{2} - 5 {}^{2}  }

r =  \sqrt{119}

r = 10.91

(s)

ab =  \sqrt{20 {}^{2}  - 16 {}^{2} }

ab = 12

s =  \sqrt{12 {}^{2} + 8 {}^{2}  }

s = 4 \sqrt{13}

s = 14.42

Step-by-step explanation:

8 0
3 years ago
Please answer the question below:​
Readme [11.4K]

Answer:

It's letter b

Step-by-step explanation:

I hope this help

4 0
3 years ago
Which linear equations have one solution? Check all that apply.
Nina [5.8K]
Its the third and the fourth one
7 0
3 years ago
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