Answer:
The total surface area is 94ftsq
lateral surface area is 70ftsq
top surface area is 12ftsq
bottom surface area is 12 ft sq
Lines <em>a</em> and <em>b</em> are parallel, so lines <em>p</em>, <em>q</em>, and <em>t</em> are considered to be transversals. To solve this, you make use of the fact that alternate interior angles are equal, as are alternate exterior angles, as are corresponding angles. Of course any linear pair of angles is supplementary.
∠1 = 90° — corresponding angle to the right angle above it
∠2 = 68° — the sum of 22° and angles 1 and 2 is 180°
∠3 = 112° — supplementary to angle 2 (and the sum of 22° and 90°, opposite interior angles of the triangle)
∠4 = 112° — equal to angle 3
∠5 = 68° — equal to angle 2; supplementary to angle 4
∠6 = 56° — base angle of isosceles triangle with 68° at the apex; the complement of half that apex angle
∠7 = 124° — supplementary to the other base angle, which is equal to angle 6; also the sum of angles 5 and 6
∠8 = 124° — alternate interior angle with angle 7, hence its equal.
Woah that looks hard and if no one answers just search it up
164+56−(3+4+1)
=220−(3+4+1)
=220−(7+1)
=220−8
=212
Answer:
Angle ABD is 16 degrees and Angle DBC is 74 degrees
Step-by-step explanation:
Question 6. x+9+11x-3=90. 12x+6=90 -6 on both sides and 12x=84 divide each side by 12 and x= 7 angle ABD is x+9 so 7 +9= 16. Angle measure of ABD is 16 degrees. Measure of angle DBC is 11x -3 so 11 times 7=77. 77-3= 74. So the measure of angle DBC is 74 degrees and this answer is right because they both add up to be 90 degrees. Hope this helped! :)
