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zysi [14]
3 years ago
11

What is the measure of angle 8 if AB = 7 and AC = 9? Round to the nearest degree.

Mathematics
2 answers:
olga55 [171]3 years ago
5 0

tan(angle) = opposite/adjacent

tan(B) = AC/AB

tan(B) = 9/7

B = arctan(9/7)

B = 52.125 which is approximate

B = 52

--------------------------------------

The final answer is choice D) 52 degrees

Marat540 [252]3 years ago
4 0

the answer is 52°

use the laws of trig

its a right triangle, so cotan 9/7 is 52°

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Please help will give brainliest answer
IgorC [24]

Answer:

42.5 units^2

Step-by-step explanation:

We can split up this shape into smaller ones.

First we can start with the large rectangle on top

We know its 9 by 3.5

9x3.5=31.5

The large rectangle is 31.5, at the end we'll add them all together

Next we can work on the small triangle on the bottom left

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Both the base and height are 2, 2x2=4   4/2=2, The area of that triangle is 2

Now we can work on the triangle on the bottom right. This time the base is 5

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Now we know the small square is 2 by 2. 2x2=4 The square's area is 4

Now we add them all up.

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8 0
3 years ago
What is the value of the expression?<br> 5(6-10)
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6 0
3 years ago
9.51 as a mixed number in a simplest form
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Below

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7 0
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Read 2 more answers
An air transport association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maxim
Flura [38]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population mean, when the population standard deviation is not provided is:

CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}

The sample selected is of size, <em>n</em> = 50.

The critical value of <em>t</em> for 95% confidence level and (<em>n</em> - 1) = 49 degrees of freedom is:

t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000

*Use a <em>t</em>-table.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}

     =6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

7 0
3 years ago
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