Answer:
24.56
Step-by-step explanation:
1.14x-5+5=23+5
1.14x=28
x is roughly equal to 24.56.
Hope this helps!
Answer:
The third one is the answer
Building B; it is around 16.35 feet taller than building A
Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?
cos y° = 6 divided by b cos y° = 6a cos
If sin f° = 8/9 and the measure of YW is 24 units, what is the measure of YX?
24 units
Answer:
Sum of interior angles of a triangle always = 180 degrees
add the individual ratios to get a sum composite ratio:
2+5+8 = 15
180 / 15 = 12
Multiply individual ratios:
{2:5:8} * 12 = 24:60:96
Check:
24 + 60 + 96 = 180
Step-by-step explanation:
I hope it's help
Answer:
(i) ∠ABH = 14.5°
(ii) The length of AH = 4.6 m
Step-by-step explanation:
To solve the problem, we will follow the steps below;
(i)Finding ∠ABH
first lets find <HBC
<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)
46° + <HBC + 90 = 180°
<HBC+ 136° = 180°
subtract 136 from both-side of the equation
<HBC+ 136° - 136° = 180° -136°
<HBC = 44°
lets find <ABC
To do that, we need to first find <BAC
Using the sine rule
= 
A = ?
a=6.9
C=90
c=13.2
= 
sin A = 6.9 sin 90 /13.2
sinA = 0.522727
A = sin⁻¹ ( 0.522727)
A ≈ 31.5 °
<BAC = 31.5°
<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)
31.5° +<ABC + 90° = 180°
<ABC + 121.5° = 180°
subtract 121.5° from both-side of the equation
<ABC + 121.5° - 121.5° = 180° - 121.5°
<ABC = 58.5°
<ABH = <ABC - <HBC
=58.5° - 44°
=14.5°
∠ABH = 14.5°
(ii) Finding the length of AH
To find length AH, we need to first find ∠AHB
<AHB + <BHC = 180° ( angle on a straight line)
<AHB + 46° = 180°
subtract 46° from both-side of the equation
<AHB + 46°- 46° = 180° - 46°
<AHB = 134°
Using sine rule,
= 
AH = 13.2 sin 14.5 / sin 134
AH≈4.6 m
length AH = 4.6 m
9 and 12 have a common factor of 3 so 9/12 = 3/4