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ArbitrLikvidat [17]
3 years ago
6

Maureen makes $15 an hour at her job, plus an 18% bonus on her salary for that day if she sells a super item. Maureen worked 5 h

ours Monday, 8 hours Tuesday and 6 hours Thursday. She sold a super item on Monday and Tuesday. What is her weekly pay?
Mathematics
1 answer:
Bad White [126]3 years ago
8 0
I think it's $320.1

15x5=75 15x8=120 15x6=90

75x.18=13.5 120x.18=21.6

75+120+90+13.5+21.6=320.1

Check if I did my math correct
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RoseWind [281]
He made 10 doallars and 50 cents thank you
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2 years ago
Which of the following situations would combine to make zero?
ZanzabumX [31]
The answer is D she started out with 250$ and then subtracted 250$
250-250=0
8 0
3 years ago
Which equation can be used to solve the problem?<br> 10 is 50 percent of what number?
Rudiy27

Answer:

x*50%=10

Step-by-step explanation:

x*50%=10

  /50%  /50%

x=20

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2 years ago
Read 2 more answers
Write an expression that represent the following. Add the sum by 5. Next, add 15 to that product,then triple the results.
Irina-Kira [14]
5+15=20
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5 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
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