Use the power rule for differentiation:
You can use this formula if you remember that a root is just a rational exponential:
![\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%5Cln%28x%29%20%3D%20%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20)
So, remembering that the derivative of the logarithm is 1/x, you have
Which you can rewrite as
![\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%7D%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B1%7D%7B4%7D-1%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%5Cdfrac%7B1%7D%7B4%7D%28%5Cln%28x%29%29%5E%7B%5Cfrac%7B-3%7D%7B4%7D%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%5Cdfrac%7B1%7D%7B4%7D%5Cdfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B%5Cln%28x%29%29%5E3%7D%7D%5Cdfrac%7B1%7D%7Bx%7D%20%3D%20%5Cdfrac%7B1%7D%7B4x%5Csqrt%5B4%5D%7B%5Cln%28x%29%29%5E3%7D%7D%20)
Answer:
16 m × 11 m
Step-by-step explanation:
The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.
The original length of gym = 20 m and original width of gym = 15 m
2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:
Length of basketball court = 20 m - (2 * 2m) = 20 m - 4 m = 16 m
Width of basketball court = 15 m - (2 * 2m) = 15 m - 4 m = 11 m
Therefore the dimensions of the basketball court is:
16 m × 11 m
Answers are A and E, this is because you can do 3:12 x 4 = 12:48 and 3:12/4 = 1:4 therefore they are all equal values
Answer:
See Explanation
Step-by-step explanation:
For an object at temperature T and supposing that the ambient temperature is Ta then we can write the differential equation that typifies the Newton law of cooling as follows;
dT/dt=-k(T-Tₐ)
So
dT/dt = 2 degrees Celsius per minute
T = 70 degrees Celsius
Ta = 25 degrees Celsius
2 = -k(70 - 25)
-k = 2/(70 - 25)
k = - 0.044
Hence we can write;
dT/dt=-(- 0.044)(95-25)
dT/dt= 3 degrees Celsius per minute
