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melomori [17]
3 years ago
5

The vertices of ΔABC are A(−3,4)​, B(−2,4)​, and C(−5,2). If ΔABC is reflected across the line y=−2 to produce the image Δ​A'B'C

', find the coordinates of the vertex B​'.
The coordinates of B​' after a reflection across the line y= -2
Mathematics
1 answer:
Mumz [18]3 years ago
3 0

The coordinates of vertex B' is P'(x,y) = (-2, -8).

<h3>How to calculate the coordinate of point by reflection</h3>

A point if reflected across the line y = -2 by means of the following formula:

P'(x,y) = P(x,y)+2\cdot [(x_{P}, -2)-P(x,y)] (1)

Where:

  • P(x,y) - Original point
  • x_{P} - x-Coordinate of point P
  • P'(x,y) - Resulting point

If we know that P(x,y) = (-2,4) and x_{P} = -2, then the coordinates of the vertex is:

P'(x,y) = (-2, 4) + 2\cdot [(-2,-2)-(-2,4)]

P'(x,y) = (-2, 4) +2\cdot (0, -6)

P'(x,y) = (-2, 4) + (0,-12)

P'(x,y) = (-2, -8)

The coordinates of vertex B' is P'(x,y) = (-2, -8). \blacksquare

To learn more on reflections, we kindly invite to check this verified question: brainly.com/question/1878272

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Given the information:

A: "The household uses gas for cooking" ⇒ P(A)= 0.18

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Symbolically:

P(A/Bc) =<u> P(A∩Bc) </u>

                   P(Bc)

The event Bc is the complement of event B, so it's probability is P(Bc)= 1 - P(B)

You can calculate the probability of B as:

P(B)= P(A∩B)+ P(Ac∩B)

Using the information of P(B/A)= 0.7 and P(B/Ac)= 0.35 you can reach the values of both intersections.

P(B/A)=<u> P(A∩B) </u>

                P(A)

P(B/A)*P(A)= P(A∩B)

P(A∩B)= 0.7*0.18= 0.126

and

P(B/Ac)=<u> P(Ac∩B) </u>

                 P(Ac)

If A and Ac are complementary events, then P(Ac)= 1 - P(A)= 1 - 0.18= 0.82

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P(B/Ac)*P(Ac)= P(Ac∩B)

P(Ac∩B)= 0.35*0.82= 0.287

The probability of B is:

P(B)= P(A∩B)+ P(Ac∩B)= 0.126+0.287= 0.413

P(Bc)= 1 - P(B)= 1 - 0.413= 0.587

And

P(A)= P(A∩B)+P(A∩Bc)

P(A∩Bc)=P(A)=-(A∩B)= 0.18-0.126= 0.054

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P(A/Bc) =<u> P(A∩Bc) </u>=<u>0.054 </u>= 0.0919≅ 0.092

                   P(Bc)     0.587

I hope it helps!

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