9.3 × 107 would be the scientific notation
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
So we need to find the sum of the first 5 terms.
You have told me that the first term is 10 meters, and that r = 0.5 per term.
With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).
Plugging in the terms that we know...
s₅=10((1-0.5⁵)/(1-0.5))
s₅=10(0.96875/0.5)
s₅=10(1.9375)
s₅=19.375
With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.
Answer:
Step-by-step explanation:
I suggest looking lessons on it online if you don't understand... It's hard to do your work especially if you don't understand it. Or if your online, go to past lessons or something.
