Assume the first integer is
![x](https://tex.z-dn.net/?f=x)
.
then we have the sequence for the 6 numbers:
![x,x+1,x+2,x+3,x+4,x+5](https://tex.z-dn.net/?f=x%2Cx%2B1%2Cx%2B2%2Cx%2B3%2Cx%2B4%2Cx%2B5)
their sum equals 519. so we have the equation
![(x)+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=519](https://tex.z-dn.net/?f=%28x%29%2B%28x%2B1%29%2B%28x%2B2%29%2B%28x%2B3%29%2B%28x%2B4%29%2B%28x%2B5%29%3D519)
now solve it.
![6x+15=519](https://tex.z-dn.net/?f=6x%2B15%3D519)
![6x=504](https://tex.z-dn.net/?f=6x%3D504)
![x=84](https://tex.z-dn.net/?f=x%3D84)
now that we know the value of
![x](https://tex.z-dn.net/?f=x)
, we can find the sequence of the integers:
Answer:
2.31 and 3.31
Step-by-step explanation:
since .81 is repeating, we can assume .31 does too
-9/10 + 3/5 - 9/10 = -1.2 and -1.2 = -1 1/5 so if we add -3/5 we get -1.8 or -1 4/5 so therefore your answer is -3/5
Answer:
2
Step-by-step explanation:
Answer:
The second option.
Step-by-step explanation: