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geniusboy [140]
3 years ago
8

Which method would you choose to solve the following system?

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Answer: combining like terms

Step-by-step explanation:

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Amir pits £3035 into a bank account. The account pays 4% compound interest each year. Work out how much money amir will have in
myrzilka [38]

Answer:

\£3840.2

Step-by-step explanation:

Let P denotes principal amount, T denotes time period and R denotes rate of interest.

Amount = P(1+\frac{R}{100})^T

Amir pits £3035 into a bank account. The account pays 4% compound interest each year.

Put P=\£3035,\,R=4\%,\,T=6

Amount = 3035(1+\frac{4}{100})^6=3035(\frac{104}{100})^6=\£3840.2

Therefore, Amir will have \£3840.2 in the account after 6 years.

7 0
3 years ago
Explain how to use multiplication to find
Sindrei [870]

A fraction x/y is a ratio between two numbers x and y.

The ratio is preserved if both x and y are scaled up or down by the same number n.

This means you can obtain any fraction equivalent to x/y by multiplying both x and y by n, i.e. (n*x)/(n*y).

Then we have 1/4 = (2*1)/(2*4) = 2/8, for example.

5 0
3 years ago
Evaluate the functions​
Anna11 [10]

Answer:

(btw the first question answer is -4, not 0)

10

Step-by-step explanation:

(btw the first question answer is -4, not 0)

So to solve the 2nd equation you substitute t with 30

so 30-2/3*30

30-20=10

6 0
3 years ago
Fill in the blank.<br>-9+____=-14​
faust18 [17]

Answer:

-5

Step-by-step explanation:

-9+x = -14

Add 9 to each side

-9+x+9 = -14+9

x = -5

4 0
3 years ago
Read 2 more answers
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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