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2 years ago

Which method would you choose to solve the following system?

Mathematics

1 answer:

gladu [14]2 years ago

3 0

Answer: combining like terms

Step-by-step explanation:

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Write 22 4/5 as a decimal

romanna [79]

change to improper fraction:

22 4/5

22*5=110+4=114

114/5

divide:

114/5=22.8

Thus, 22 4/5 as a decimal is 22.8

7 0

3 years ago

Read 2 more answers

What is a - 5 - 6a + 3

Yakvenalex [24]

Answer:

-7-5a

Step-by-step

i simplified it if thats what it meant

4 0

2 years ago

Can you simplify 14x+11 please??

ad-work [718]

Answer:

It cannot be further simplified

Step-by-step explanation:

11 is a prime number, so there are no numbers that can go into 14 and 11 (besides 1 and 1 would not simplify the problem)

6 0

3 years ago

Noa hopes to pick the winning ticket during her math class’s raffle. the student who picks the ticket with a true statement will

Natali5045456 [20]

Answer: The winning ticket is $2(x-6)=-35$ is equivalent to $2x=-23$ .

Step-by-step explanation:

Let's check all the options

$4(x-5)=35$ is not equivalent to $4x=40$

$\text{since }4(x-5)=35\\\Rightarrow4x-20=35\\\Rightarrow4x=35+20\\\Rightarrow4x=55$

$8(x-7)=35$ is not equivalent to $8x=28$

$\text{since }8(x-7)=35\\\Rightarrow8x-56=35\\\Rightarrow8x=35+56\\\Rightarrow8x=91$

$2(x-6)=-35$ is equivalent to $2x=-23$

$\text{since }2(x-6)=-35\\\Rightarrow2x-12=-35\\\Rightarrow2x=-35+12\\\Rightarrow2x=-23$

$9(x-6)=-35$ is not equivalent to $9x=-29$

$\text{since }9(x-5)=-35\\\Rightarrow9x--40=-35\\\Rightarrow9x=-35+40\\\Rightarrow9x=5$

Thus, the winning ticket is $2(x-6)=-35$ is equivalent to $2x=-23$ .

4 0

2 years ago

Read 2 more answers

What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4

Alecsey [184]

Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: $f(x)=\dfrac{3x^2}{x^2-4}$

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. $x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2$

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at $y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}$

i.e. $y=\dfrac{3}{1}=3$

Hence, f(x) will have horizontal asymptote at y=3.

3 0

3 years ago