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lora16 [44]
3 years ago
15

The driver of a car traveling at a speed of 40 miles per hour had to stop the car quickly. If the driver`s reaction time was 34

of a second, approximately how many feet did the car travel during the driver`s reaction time? (1 mile = 5,280 feet)
Mathematics
1 answer:
natulia [17]3 years ago
4 0

Answer:

The car travel 44 feet during the driver`s reaction time.

Step-by-step explanation:

The sentence "If the driver`s reaction time was 34 of a second"  has to be changed as "If the driver`s reaction time was 3/4 of a second"

If the driver drives at a speed of 40 miles per hour, it means s/he travels

40 × 5280 = 211200 feet per hour.

1 hour is 60 minutes and 1 minute is 60 seconds.

That is, 1 hour is 3600 seconds.

Therefore the driver travels \frac{211200}{3600} feet in a second.

And since the reaction time is \frac{3}{4} =0.75 of a second, the car travels \frac{211200}{3600 } * \frac{3}{4}=44 feet during the reaction time.

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Answer:

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Step-by-step explanation:

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The difference between the volume of the spheres is 3428.88 cubic feet

Explanation:

Given that one sphere has a radius of 11 feet.

A second sphere has a radius of 8 feet.

<u>Volume of the 1st sphere:</u>

The formula to determine the volume of the sphere is given by

V=\frac{4}{3} \pi r^3

Volume of the 1st sphere is given by

V=\frac{4}{3}(3.14)(11)^3

V=\frac{4}{3}(3.14)(1331)

V=\frac{16717.36}{3}

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Volume of the 2nd sphere is given by

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V=\frac{4}{3}(3.14)(512)

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The volume of the 2nd sphere is 2143.57 cubic feet.

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Difference = Volume of the 1st sphere - Volume of the 2nd sphere

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Difference = 3428.88 cubic feet.

Hence, the difference between the volume of the spheres is 3428.88 cubic feet.

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