Y = 3x + 5 because the slope is 3/1 and 0 = 5
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = = 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
Step-by-step explanation:
The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept. In our equation, y = 6x + 2, we see that the slope of the line is 6.
Hope this helps :)
Answer:
7:00pm
Step-by-step explanation:
4 sqrt(400) / 4 sqrt(5)
sqrt(400) =20
4 *20
--------
4 sqrt(5)
the 4's on the top and bottom cancel
20
--------
sqrt(5)
I was taught never to leave a sqrt in the denominator
so you need to multiply by sqrt (5) in the numerator and the denominator
20* sqrt(5)
--------
sqrt(5)* sqrt(5)
20* sqrt(5)
--------
5
= 4 sqrt(5)