So you would start with the square and do 18 times 18 which equals 324 then for the triangle it's base times height divided by two so 9 times 18 divided by 2 which equals 81 then you add the triangle plus the square and your final answer is

answer:405

8 0

3 years ago

Read 2 more answers

(50 Points Please help)

Elina [12.6K]

Answer:

A. Length of a Tour Bus ↔ #2. 1.1 × 10¹ meters

B. Width of an apple ↔ #3. 4 × 10⁰ centimeters

C. Distance from Earth to a Satellite ↔ #6. 8 × 10² kilometers

D. Thickness of a human hair ↔ #5. 9 × 10¹ micrometers

Step-by-step explanation:

The length of a tour bus should be measured in meters. It sure is way less than 1 kilometer and way more than a few centimeters. It could be about some meters, more than 5 meters, may be between 10 meters and 15 meters.

The measurement in the box # 2. is 1.1 × 10¹ meters, which is equivalent to 1.1 × 10 meters = 11 meters. Thus, this is a reasonable length.

B. Width of an apple.

The most appropriate unit to measure the width of an apple should be centimeter. It certainly is shorter than 1 meter and bigger than 1 mm.

The width of an apple could be, more or less, around 8 centimeters. The only measurement in the boxes that is in that order is that in the box #3., 4 × 10⁰ centimeters, because 10⁰ = 1, so 4 × 10⁰ = 4 × 1 = 4 centimeters.

C. Distance from Earth to a Satellite

The distance from Earth to a satellite should be measured in kilometers.

You can find in the internet that the distances of the satellites are between 700 kilometers and 36,000 kilometers.

The number in the box #1 is too big, in the order of ten trillions of kilometers, because one trillion is 10¹²; thus that is nonseasonal (too big).

The number in the box #6 is 8 × 10² kilometers, which is equal to 8 × 100 = 800 kilometers.

Thus, 8 × 10² kilometers (box #6) is the most reasonable measurement for the distance from Earth to a Satellite

D. Thickness of a human hair

Of course, kilometers, meters, centimeters and even millimeters are units too big to measure the thickness of a human hair.

One micrometer is 10⁻⁶ meters or 10⁻³ millimeters.

In the internet you can find that diameter of the human hair is in the range from 17 micrometers to 181 micrometers.

The measurement in the box #5. is 9 × 10¹ micrometers, which is equivalent to 9 × 10 = 90 micrometers.

Thus, 9 × 10¹ micrometers is the most reasonable measurement for the thickness of a human hair.

5 0

3 years ago

Read 2 more answers

Me podrían ayudar y explicarme el proceso please

kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

$\frac{1}{x} =\frac{20kg}{7653kg}$

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

$x=\frac{1*7653kg}{20kg}$

$x=382.65$

Como una caja no puede ser un numero decimal, redondeamos.

$x=383$

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

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La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

$\frac{1}{x}=\frac{20kg}{9500kg}$

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

$x=\frac{1*9500kg}{20kg}$

$x=475$

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

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Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

$\frac{1}{873}=\frac{20kg}{x}$

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

$x=\frac{873*20kg}{1}$

$x=17460kg$

Este sería el peso de 873 cajas.

5 0

3 years ago

Write an explicit formula for the sequence 3,-9,27,-81

Dominik [7]

The initial value is 3. The common ratio is -9/3 = -3. The general formula is
.. an = a1*r^(n-1)

So, for your values, ...
.. an = 3*(-3)^(n -1)

7 0

3 years ago